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3 years ago

Dille..) In rectangle ABCD, AD= 7 and CD= 24. FindBD.

Mathematics

1 answer:

Alexxandr [17]3 years ago

8 0

Answer:

Step-by-step explanation:7^2+24^2=49+576=625 624^.5=25

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Consider h(x)=x^2+8+15. identify its vertex and y-intercept.

OleMash [197]

Answer:

Vertex: (-4, -1)

Y-intercept: (0, 15)

Step-by-step explanation:

Given the quaratic function, h(x) = x² + 8x + 15:

In order to determine the vertex of the given function, we can use the formula, $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ .

<h3>Use the equation: $[x = \frac{-b}{2a}, h(\frac{-b}{2a})]$ </h3>

In the quadratic function, h(x) = x² + 8x + 15, where:

a = 1, b = 8, and c = 15:

Substitute the given values for <em>a</em> and <em>b</em> into the equation to solve for the x-coordinate of the vertex.

$x = \frac{-b}{2a}$

$x = \frac{-8}{2(1)}$

x = -4

Subsitute the value of the x-coordinate into the given function to solve for the <u>y-coordinate of the vertex</u>:

h(x) = x² + 8x + 15

h(-4) = (-4)² + 8(-4) + 15

h(-4) = 16 - 32 + 15

h(-4) = -1

Therefore, the vertex of the given function is (-4, -1).

<h3>Solve for the Y-intercept:</h3>

The <u>y-intercept</u> is the point on the graph where it crosse the y-axis. In order to find the y-intercept of the function, set x = 0, and solve for the y-intercept:

h(x) = x² + 8x + 15

h(0) = (0)² + 8(0) + 15

h(0) = 0 + 0 + 15

h(0) = 15

Therefore, the y-intercept of the quadratic function is (0, 15).

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2 years ago

Given f '(x) = (x + 1)(6 + 3x), find the x-coordinate for the relative minimum on the graph of f(x).

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Answer:

x = -1

Step-by-step explanation:

The easiest way is just to find the antiderivative and graph. The antiderivative is $x^{3} + 4.5x^{2} + 9x + C$ . Graphing this with any C shows that $x=-1$ is the relative minimum.

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3 years ago

Use lagrange multiplier techniques to find the local extreme values of f(x, y) = x2 − y2 − 2 subject to the constraint x2 + y2 =

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Given $f(x,\ y)=x^2-y^2-2$ subject to the constraint $x^2+y^2=16$

Let $g(x,\ y)=x^2+y^2$ .

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$\nabla f(x,\ y)=\langle2x,-2y\rangle$ and $\nabla g(x,\ y)=\langle2x,2y\rangle$

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$\langle2x,-2y\rangle=\lambda\langle2x,2y\rangle=\langle2\lambda x,2\lambda y\rangle$

$\lambda=\pm1$

It can be seen that $f(x,\ y)=x^2-y^2-2$ has local extreme values at the given region.

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3 years ago

The table shows the distance Allison drove one day of her vacation. Is the relationship between the distance and the time propor

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Answer:

hope that it helps you any

Step-by-step explanation:

first hour she drove 60mi

second hour she drove 50mi

third hour she drove 70mi

fourth hour she drove 20mi

fifth hour she drove 75mi

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take 275 divide it by 5 you get an average of 55mph

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3 years ago

15 points

melisa1 [442]

Clockwise 270 degrees is the answer

5 0

3 years ago

Read 2 more answers

Dille..) In rectangle ABCD, AD= 7 and CD= 24. FindBD.​

Dille..) In rectangle ABCD, AD= 7 and CD= 24. FindBD.