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Anon25 [30]
3 years ago
9

Is 5.243 greater, equal to ,or less than 5.4?

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
8 0
5.243 is less than 5.4
larisa [96]3 years ago
7 0

Answer:

5.243 is less than 5.4....

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The ravens scored 13 more than three times number points that the bengals scored in their last game. If the ravens scored 40 poi
katrin2010 [14]

The score of Raven is 9 points

<em><u>Solution:</u></em>

Let the point scored by bangal be"x"

Score of Raven = 40 points

Given that,

The ravens scored 13 more than three times number points that the bangals scored in their last game

Score of raven = 13 + 3(score of bangal)

40 = 13 + 3x

Solve the above equation for x

3x = 40 - 13

3x = 27

x = 9

Thus the score of Raven is 9 points

5 0
3 years ago
In a box of 500 colored balls, 75 are black, 150 are green, 175 are red, 70 are white, and 30 are blue. what are the probabiliti
Oksanka [162]
If we want to select a ball of each colour we have to extract 175+150+75+70+1=471 balls

P=471/500 is the answer
4 0
3 years ago
3x - y = 0<br> 2x - y = 1
9966 [12]
Answer: See below

Explanation:
Solve this system of equation using elimination method:

3x - y = 0
2x - y = 1
________
3x - y = 0
-1(2x - y = 1)
_________
3x - y = 0
-2x + y = -1
_________
X = -1

We know that x = -1 now let’s plug it in the one of the equation to find y:

2x - y = 1
2(-1) - y = 1
-2 - y = 1
-y = 3
y = -3

8 0
3 years ago
How u solve 55-[(5*2×3)-5*2]
slava [35]

Answer:

35

Step-by-step explanation:

55-[(5x2x3)-5x2]

55-[30-5x2]

55-20

35

6 0
3 years ago
X+y+z =4
cestrela7 [59]
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian : 
Akar-akar persamaan lama :  x1 dan x2
                                             
Akar-akar persamaan baru :  xA dan xB
                                             xA = 2x1 - 1
                                             xB = 2x2 - 1
                                             xA + xB  = (2x1 - 1) + (2x2 - 1)
                                                           = 2 (x1 + x2) - 2
                                                           = 2 () - 2
                                                           = 3 - 2
                                              xA + xB = 1
    
                                              xA . xB = (2x1 - 1) (2x2 - 1)
                                                          = 4 x1.x2 - 2(x1 + x2) + 1
                                                          = 4.(-) - 2() + 1
                                                          = -2 - 3 + 1
                                              xA . xB = -4
    
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
                                              x² - x - 4 = 0

</span></span>
4 0
4 years ago
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