1) (3-x) x (3+x)
2) 5(5-x) x (5+x)
3) (3v-wy) x (3v+wy)
4) 2(k-m) x (k+m) x (k^2+m^2)
5) (ab-4c) x (ab+4c)
Brainliest?
Answer:
Step-by-step explanation:
2nd
3th
What we use?
We use that
and
Answer:
height = 20.5068 m
Step-by-step explanation:
Given the data in the question;
First, lets calculate the amplitude, midline and period of 8minutes
Amplitude = 35 / 2 = 17.5
|A| = 17.5
A = - 17.5 { since the wheel starts at 6 o clock }
midline C = (35/2) + 3
C = 17.5 + 3
C = 20.5
And period is 8 minutes
⇒ 2π/B = 8
8B = 2π
B = 2π/8 = π/4
So our equation will be in the form of;
y = h(t) = Acos(B×t) + C
∴ h(t) = -17.5cos( π/4×t) + 20.5
Now, How high are you off the ground after 6 minutes
⇒ height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( 4.71238898) + 20.5
height = -17.5 × cos( 4.712) + 20.5
height = -17.5 × -0.00038898 + 20.5
height = 0.0068 + 20.5
height = 20.5068 m
We are given that
Max's grade on the first math exam was a 94
so, first exam grade =94
His grade on his seond math exam was an 89
so, second exam grade =89
change in grade=(first exam grade)-(second exam grade)
change in grade=94-89
change in grade=5
Percentage = ( change in grade)/( first exam grade) *100
so, percentage is
so,
the percent of change in Max's grade to the nearest whole percentage was 5%..........Answer
Answer:
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Step-by-step explanation:
I Think, if the other person gets it right listen to them