Answer:
C) independent variable = age
dependent variable = reaction time in milliseconds
Step-by-step explanation:
The linear regression statistical test is best used for research experiment where there is a single dependent and one independent variable whjre both variables are numeric. In the given options above, the city of residence, gender, college major and political affiliation are all possible categorical variables and age, salary, miles driven and reaction time are all numerical variables. Hence, the best situation in which to use linear regression is a test where both the independent and dependent variables are either age, salary, reaction time or miles driven.
Answer:
- 1.9f - 18
Step-by-step explanation:

Answer:
y < 1
Step-by-step explanation:
graphing with inequality
A. False. The data is quantitative because we're dealing with numeric values instead of things like names, colors, etc.
B. False. The row categories are "students" and "teachers"
C. True. This value (2) is in the "teachers" row and "does not wear glasses" column.
D. False. The value 32 represents the number of students who wear glasses. See row1, column1
E. True. Look at the last value of the "teachers" row.
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In summary, the answers are: C and E
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.