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4 years ago

SOMEONE PLEASE HELP ME!!!!! URGENT

Mathematics

1 answer:

IgorLugansk [536]4 years ago

8 0

Answer:

AB=14

Step-by-step explanation:

Since there are 360° in a circle we can do 140°/360°=7/18

To find AB we can do (7/18)*(6^2)=(7/18)*(36)=14

AB=14

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(1x) +(3x)+(7x-10)= 180

Dimas [21]

Combine the x terms:
11x-10=180
Add Both sides by 10:
11x=190
Divide both sides by 11:
X=190/11

4 0

3 years ago

Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compound

Natalija [7]

Given info:

Compound Interest = Rs.1290

Rate of Interest = 15% p.a

Time = 2 years

<h3>Formula we have to know:-</h3>

$\dag{\underline{\boxed{\sf{C.I = P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1}}}}$

<u>Where</u>

C.I = Compound Interest

P = Principle

R = Rate of Interest

N = Time

$\textsf{ \underline{Solution-}}\\$

Here

C.I = Rs.1290

R = 15%

N = 2 years

Principle = ?

Now,Calculating the sum (Principle) borrowed by Rachna

$\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}$

Substituting the given values

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}$

$\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}$

$\quad{: \implies{\sf{1290 = P \times {0.3225}}}}$

$\quad{: \implies{\sf{\dfrac{1290}{0.3225} = P}}}$

$\quad{: \implies{\sf{\dfrac{1290 \times 1000}{0.3225 \times 1000} = P}}}$

$\quad{: \implies{\sf{\dfrac{12900000}{3225} = P}}}$

$\quad{: \implies{\sf{\cancel{\dfrac{12900000}{3225}} = P}}}$

$\quad{: \implies{\sf{Rs.4000 = P}}}$

$\quad{\dag{\underline{\boxed{\tt{\blue{Principle} = \purple{Rs.4000 }}}}}}$

$\begin{gathered}\end{gathered}$

<u>Hence,</u>

The sum (Principle) is Rs.4000.

3 0

3 years ago

2. Ramone and his wife had $72,380.90 in combined gross income in 2010. They had $8,295.00 in various adjustments and deductions

MAVERICK [17]

Let x = taxable income = difference of gross income and deductions T = income tax paid = amount sent to the government Use the "filing jointly" chart on the right side. You'll use the second row of that chart since subtracting $72,380.90-$8,295.00 leads to a value between 16750 and 68000. That second row turns into this equation T=1675+0.15(x-16750<span>) w</span>here <span>16750<x≤68000</span>

4 0

3 years ago

After how many seconds, rounded to the nearest hundredth, did the ball hit the ground? h(t)=-16t^2+150

Setler [38]

Answer:

Step-by-step explanation:

I got this

h=-16t squared +150/t

4 0

3 years ago

I need help thanks on both

Masja [62]

Answer:

the answer to the second one is (205 - 15)/2.

Lilly has 110.

Severus has 95.

Step-by-step explanation:

Because 205-15 = 190 so if you divide that by 2 then you will get the amount that Severus had which is 95 meaning that Lilly also has 95 but since she has 15 points higher then she has 110 so 95+110=205.

5 0

3 years ago