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marta [7]
3 years ago
10

Help pls no links pls​

Mathematics
2 answers:
AleksandrR [38]3 years ago
8 0

Answer:

13.7 budddy

Step-by-step explanation:

Leni [432]3 years ago
7 0

Answer: 13.7

Step-by-step explanation:

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Use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.) −
aleksley [76]
When it comes to laplace equations, there are transformation equations to follow. Generally, when you want to transform a laplace equation, you change the equation from f(t) to F(s). If you do the reverse, it is called the reverse laplace equation.

Based on the given, the useful transformation equation is shown in the attached picture.

When the term is s^2, that must mean that the equation is 1!/s^(1+1) to yield 1/s^2. This means that n=1. Taking the reciprocal s^2 must be equal to 1/t. Thus, for the first term, -11s^2 is equal to -11/t. For the second term, n must be equal to 6 so that 6!/s^(6+1) would yield 720/s^7. Thus, 720s^7 is equal to 1/t^6. 

Hence, the transformed equation is -11/t - 1/t^6

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3 years ago
Solve 10 -4(2.4 • 3.5)2 + 0.12
scZoUnD [109]
<span>10-4(2.4 • 3.5)2 + 0.12 = </span>-57.08 
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3 years ago
What is the answer to 7+4p-6
katovenus [111]


1+4p

the answer cant be simplified any further than this.

4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Chuge%7B%5Cgreen%7D%5Cfcolorbox%7Bblue%7D%7Bcyan%7D%7B%5Cbf%7B%5Cunderline%7B%5Cred%7B%5C
MariettaO [177]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;

\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}

\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}

\qquad \sf  \dashrightarrow  \:m =  - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)

\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~

\qquad \sf  \dashrightarrow \:y =  - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :

\qquad \sf  \dashrightarrow \:y <  - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

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2 years ago
Como resolver una fraccion heterogeneas de suma de 1/4 y 1/8
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I can’t understand because I speak English
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