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geniusboy [140]
3 years ago
14

Universal Containers has the following requirements:• Enable VIP community access once a customer has reached $1 million in reve

nue.• Maintain customer revenue in Salesforce.• All customers must have access to the general customer community.• VIP customers must have access to VIP information in the community.• The number of profiles in Salesforce must be limited.How should the Salesforce Admin provide VIP users access to the VIP information?A. Create a profile that has permissions to the VIP information and assign it to the VIP community users.B. Create a permission set that has permissions to the VIP information and add it to VIP customers.C. Create a sharing set that allows VIP customers to access VIP information.D. Create a sharing rule that allows VIP customers to access VIP information.
Computers and Technology
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

A. Create a profile that has permissions to the VIP information and assign it to the VIP community users.

Explanation:

Salesforce is a customer rapport management platform that is based on the cloud. There are program applications for sales, marketing and services. The platforms are utilized to achieve an enhanced relationship with customers because they have a better understanding the need of their customers and how to solve their problems by organization and managing their customers' information and interactions.

VIP users will get access to the information they want when there are permissions set for the VIP users. VIP information will be given to the VIP customers in order for them to carry out activities that they need to do to execute their job.

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// PrintStrings // Traverse the 2D character array "strings" and print each of the contained strings.// See the example outputs
anzhelika [568]

Answer:

C++.

Explanation:

void printStrings(char strings[NUM_STRINGS][STRING_LENGTH]) {

   // Multi dimension array can be traversed through multi-level loops

   for (int i = 0; i < NUM_STRINGS; i++) {

       for (int j = 0; j < STRING_LENGTH; j++) {

           cout<<"<<strings[i][j]<<";

       }

       cout<<endl;

   }

}

Output would be like this, depending on the size of NUM_STRINGS;

"One"

"Two"

"Three"

....

6 0
3 years ago
Create a class called Hokeemon that can be used as a template to create magical creatures called Hokeeemons. Hokeemons can be of
Viefleur [7K]

Answer:

See Explaination

Explanation:

/*****************************************Hokeemon.java********************************/

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class Hokeemon {

private String name;

private String type;

private int age;

public Hokeemon(String name, String type, int age) {

super();

this.name = name;

this.type = type;

this.age = age;

}

public Hokeemon() {

this.name = "";

this.type = "";

this.age = 0;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public String getType() {

return type;

}

public void setType(String type) {

this.type = type;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

public String liveIn() {

if (this.type.equalsIgnoreCase("dwarf")) {

return "Mountain";

} else if (this.type.equalsIgnoreCase("elf")) {

return "Dale";

} else if (this.type.equalsIgnoreCase("fairy")) {

return "Forest";

} else {

return "Shire";

}

}

public boolean areFriends(Hokeemon other) {

if (this.type.equalsIgnoreCase(other.type)) {

return true;

} else if ((this.type.equalsIgnoreCase("dwarf") && other.type.equalsIgnoreCase("elf"))

|| (this.type.equalsIgnoreCase("elf") && other.type.equalsIgnoreCase("dwarf"))) {

return true;

} else if ((this.type.equalsIgnoreCase("hobbit") && other.type.equalsIgnoreCase("fairy"))

|| (this.type.equalsIgnoreCase("fairy") && other.type.equalsIgnoreCase("hobbit"))) {

return true;

} else {

return false;

}

}

public static Hokeemon[] getData(String file) {

Hokeemon[] hokeemons = new Hokeemon[8];

int i = 0;

try {

Scanner scan = new Scanner(new File(file));

while (scan.hasNextLine() && i < hokeemons.length) {

String line = scan.nextLine();

String[] data = line.split("\\s+");

String name = data[0];

String type = data[1];

int age = Integer.parseInt(data[2]);

hokeemons[i] = new Hokeemon(name, type, age);

i++;

}

scan.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

return hokeemons;

}

public static String getBio(Hokeemon[] hokeemons) {

String s = "";

for (Hokeemon hokeemon : hokeemons) {

s += "I am " + hokeemon.getName() + ": Type " + hokeemon.getType() + ": Age=" + hokeemon.getAge()

+ ", I live in " + hokeemon.liveIn() + "\n";

s += "My friends are: ";

for (Hokeemon hokeemon2 : hokeemons) {

if (hokeemon.areFriends(hokeemon2) && !hokeemon.equals(hokeemon2)) {

s += (hokeemon2.getName() + " ");

}

}

s += "\n";

}

return s;

}

atOverride

public String toString() {

return "Name " + name + ": Type " + type + ": Age=" + age + "\n";

}

}

/*******************************HokeemonMain.java**************************/

import java.util.Arrays;

public class HokeemonMain {

public static void main(String[] args) {

Hokeemon[] hokeemons = Hokeemon.getData("data.txt");

System.out.println(Arrays.toString(hokeemons));

System.out.println(Hokeemon.getBio(hokeemons));

}

}

/**********************************data.txt********************/

Noddy Dwarf 4

Legolas Elf 77

Minerva Fairy 33

Samwise Hobbit 24

Merry Hobbit 29

Warhammer Dwarf 87

Ernedyll Elf 19

Frodo Hobbit 18

3 0
3 years ago
Which of the following calculations would evaluate to 12?
lidiya [134]

Answer:

the answer for this is 3*(6+2)/2)

8 0
3 years ago
How many bits are required to encode an image that is 25 pixels wide and 50 pixels tall, if you encode each pixel with 12 bits o
AURORKA [14]

Just multiply all numbers to get the total number of bits:

25*50*12 = 15000 bits.

3 0
3 years ago
_______ is a variation of phishing that uses voice communication technology to obtain the information the attacker is seeking.
Zanzabum
It's voice phishing but it's also sometimes referred to as vishing 
4 0
3 years ago
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