One of the founders of Foursquare is Dennis Crowley. The other is Naveen Selvadurai. I know you didn't ask for both but I wanted to give them to you just in case. I hope this helps! (:
Answer:
The program to this question can be given as:
Program:
#include <stdio.h> //include header files
#include<math.h>
int main() //main method
{
double treeHeight = 0.0; //declare variables
and assign value
double shadowLength = 0.0;
double angleElevation = 0.11693706;
// (0.11693706 radians = 6.7 degrees) convert number into angle.
shadowLength = 17.5;
treeHeight = shadowLength * tan(angleElevation); //convert number into angle
printf("Tree height: %lf\n", treeHeight); //print value.
return 0;
}
Output:
Tree height: 2.055778
Explanation:
In the above C language program firstly we include the headers. In this header file, we include a (math.h) header file this file helps to use the math function. Then we declare the main method in the main method we declare the variable that is given in the question that are treeHeight, shadowLength , angleElevation. All the variable datatype is double because it stores the floating-point value. Then we apply the formula that is treeHeight = shadowLength * tan(angleElevation). In this formula, the treeHeight variable holds the value. Then we print the variable value for print the double value we use the lf(that is long float).
Explanation:
1. How many computers do you want to connect or how big the network should be?
This would tell us what kind of a network need to be built. It can be LAN/MAN/WAN
2. The location where network needs to be built?
We have to check the geographic condition too before creating a network
3. What is the budget?
Based on the budget only, we can decide the wires to be used if require we can negotiate the budget so that we can create effective network
4. Will I get an additional resources to work?
This is essential to estimate the time that is required to complete the task.
5. When the project needs to be completed?
This is crucial because a business might be planned thereafter.
