Answer:
X has travelled 4 times as far as Y
X is moving 2 times as fast as Y
Explanation:
Because x=1/2at²(get rid of the first portion of x=vt+1/2at² because initial v is 0 which multiplies to 0). If the acceleration is set to for example 10 (keep this constant for both X and Y) and we use t=1 and t=2 for time (as the time travelled of X is twice that of Y). Plugging this into the equation, at t=1, x=4. At t=2, x=20. 20 is four times greater than 5, so X has travelled 4 times as far as Y.
To find the difference in speed between the two objects, use the equation 
. Since the initial velocity is 0, that part can just be removed from the equation. With v=at, it is easy to see that if the time plugged in is twice for one than the other (and the acceleration is the same for both), the final result will be twice of the other as well. For example: If the acceleration is 10 again for both, then v=10t. If t is 1, the velocity is 10. If t is 2, the velocity is 20.
Since you already have the equation, all you need to do is pick two values of x.
For example, when x = 0, you get y = 7/4(0) + 2 = 2. So the line passes through the point (0, 2). When x = 4 (picked to cancel the 4 in the fraction), you get y = 7/4(4) + 2 = 9, so the line also passes through the point (4, 9).
You can describe an entire line by any two points that it contains. So plot these two points, then connect the dots with a line passing through them both.
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