<h3>Answer: 6pi radians</h3>
(this is equivalent to 1080 degrees)
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Explanation:
f(x) = sin(x/3)
is the same as
f(x) = 1*sin( (1/3)(x-0) )+0
and that is in the form
f(x) = A*sin( B(x-C) )+D
The letters A,B,C,D are explained below
A = helps find the amplitude
B = 2pi/T, where T is the period
C = determines phase shift (aka left/right shifting)
D = determines vertical shift = midline
All we care about is the value of B as that is the only thing that is connected to the period T
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Compare f(x) = 1*sin( (1/3)(x-0) )+0 with f(x) = A*sin( B(x-C) )+D and we see that B = 1/3, so,
B = 2pi/T
1/3 = 2pi/T
1*T = 3*2pi ... cross multiply
T = 6pi
The period is 6pi radians. This is equivalent to 1080 degrees. To convert from radians to degrees, you multiply by (180/pi).
Substituting the values given, we get
(2)*(3) + 4 ;
Using BODMAS
We get
6 + 4
= 10
Answer:
x = 14
Step-by-step explanation:
Extend line AB so that it intersects ray CE at point G. Then angles BGC and BAD are "alternate interior angles", hence congruent.
The angle at B is exterior to triangle BCG, and is equal to the sum of the interior angles at C and G:
138 = (376 -23x) +(x^2 -8x)
Subtracting 138 and collecting terms we have ...
x^2 -31x +238 = 0
For your calculator, a=1, b=-31, c=238.
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<em>Additional comment</em>
You will find that the solutions to this are x = {14, 17}. You will also find that angle BCE will have corresponding values of 54° and -15°. That is, the solution x=17 is "extraneous." It is a solution to the equation, but not to the problem.
For x=14, the marked angles are A = 84°, C = 54°.
The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>
Let x be the speed of the walkway.
(2.8 + x) = speed of child moving in direction of the walkway
(2.8 - x) = speed of child moving against the direction of the walkway
Travel time = distance/speed
Travel time of child moving in direction of walkway = 23/(2.8+x)
Total elapsed time given = 29s
23/(2.8 + x)+ 23 / (2.8-x) = 29
LCD = (2.8 + x)(2.8 - x)
simplifying the equation, we get
Speed of walkway = 1.84 m/s
The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
To learn more about Speed refer to:
brainly.com/question/4931057
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