A.) 0.35x + 42 ≤ 70
She wants the truck for one day, which will cost $45. We don't know how far the truck is traveling so that is the variable. She cannot spend more than $70, since that is her budget.
b.) Solve for x using the above equation:
0.35x + 42 ≤ 70
0.35x ≤ 28
x ≤ 80
Judy can drive 80 miles
Answer:
Takeru bought 72 eggs and baked 18 soufflés .
Step-by-step explanation:
Let
e = number of eggs Takeru bought.
s = number of soufflés Takeru bought.
Then we know that Takeru bought 4 times as many eggs as he baked soufflés, therefore:
And since for every soufflés Takeru bakes he uses 3 eggs, and after backing he has 18 eggs left, we have:
<em>This says that from 
eggs there are 18 eggs left after Tkeru used three eggs for each soufflé.</em>
Now we have two equations:
We put the value of e from equation (1) into equation (2) and solve for s and get:
Thus
Number of eggs Takeru bought = 72.
Number of soufflés Takeru bought = 18.
We aer goint to eliminate the x's
multiply first by -5 and 2nd by 2
so that is B
The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.
To get all the same birthday you'd have to the chance of one birthday, 1/365 and multiply this by itself 10 times. This will produce a very tiny number. In standard form this would be 2.3827x10'-26 or in normal terms: 0.23827109210000000000000000, so very small.
The questions is, when z=9, 3z = ? When you multiply 3*9, you get 27
