Answer:
Y² = (1-X) / 2
Step-by-step explanation:
According To The Question, We Have
X= Cos2t & Y= Sint
the cartesian equation of the curve is given by Y² = (1-X) / 2 .
Proof, Put The Value of X & Y in Cartesian Equation, We get
Sin²t = {1-(1-2×Sin²t)} / 2 [∴ Cos2t = 1 - 2×Sin²t]
Taking R.H.S
- (1-1+2×Sin²t)/2
- 2Sin²t/2 ⇔ Sin²t = L.H.S (Hence Proved)
It should be B let me know if im correct
Given the following points:
Point P: (-4, 3)
Point Q: (9, 14)
To be able to find the midpoint of the line segment, we will be using the following formula:
We get,
Therefore, the midpoint of the line segment is 5/2, 17/2.
In this equation x is equal to 5/26.
hello :<span>
<span>an equation of the circle Center at the
O(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = AO
r² = (AO)²
r² = (4-0)² +(5-0)² = 16+25=41
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through B(4, 5) is : x² +y² = 41</span></span>
x² +y² - 41=0
