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MAXImum [283]
3 years ago
5

What is the answer to (7j+1/8q+3+-(5/8q-11+2j) 20 points

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

the answer is 5j-1/2q plus 14

Step-by-step explanation:


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Simplify (4x+5y) (2x-3y) + 3xy
zalisa [80]

Answer:

the answer is 8x^2+xy-15y^2

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Help me plsss!!!! plsss!!!
Sholpan [36]

Step-by-step explanation:

Substitute the x values from the table into the equation.

<u>Substitute -4 into the equation:</u>

y = -3(-4) + 4

y = 12 + 4

y = 16

<u>Substitute -2 into the equation:</u>

y = -3(-2) + 4

y = 6 + 4

y = 10

<u>Substitute 0 into the equation:</u>

y = -3(0) + 4

y = 0 + 4

y = 4

<u>Substitute 2 into the equation:</u>

y = -3(2) + 4

y = -6 + 4

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3 years ago
4.2x-1.4y=2.1 <br> Solve for y
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Step-by-step explanation:

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3 years ago
What line is a transversal​
Dvinal [7]

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Read 2 more answers
In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a
UNO [17]

Answer:

T = - 7.5 Cos π/12( t - 4 ) + 10.5

Step-by-step explanation:

Given that the

Maximum temp. = 18 degree Celsius

Minimum temp. = 3 degree Celsius

The half way between 10 am and 10 pm is 4 am

The sine and cosine functions can be used to model fluctuations  in temperature data through out the year. An equation that can be used to model these data is of the form:

T = A cos B(t - C) + D, where A,B,C,D, are constants, T is the  temperature in °C and t is the hour (1–24)

A = amplitude = (Tmax - Tmin)/2

A = (3 - 18)/2 = - 15/2 = -7.5 ( note : after midnight)

B = 2π/24 = π/12

C = units translated to the right

C = 4

D = ymin + amplitude = units translated up

D = 7.5 + 3 = 10.5

The formula of the trigonometric function that models the temperature T in Johannesburg t hours after midnight we be

T = - 7.5 Cos π/12( t - 4 ) + 10.5

3 0
4 years ago
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