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ollegr [7]
3 years ago
7

Noah drew a scaled copy of Polygon P and labeled it Polygon Q. If the area of Polygon P is 5 square units, what scale factor did

Noah apply to Polygon P to create Polygon Q?

Mathematics
2 answers:
vredina [299]3 years ago
8 0

Answer:

The scale factor is 3

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

x -----> area of polygon Q

y ----> area of polygon P

so

z^{2}=\frac{x}{y}

we have

y=5\ units^2

<em>Find the area of polygon Q</em>

Divide the polygon Q into five squares

see the attached figure N 2

The area of polygon Q (area of the  five squares)  is

x=5(3^2)=45\ units^2

<em>Find the scale factor</em>

z^{2}=\frac{x}{y}

we have

x=45\ units^2

y=5\ units^2

substitute

z^{2}=\frac{45}{5}

z^{2}=9

square root both sides

z=3

therefore

The scale factor is 3

Svetach [21]3 years ago
5 0

Answer:

3 is the answer

Step-by-step explanation:

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25,830
First do prime factorization on 42 that is 5*3*3
82 that is 41*2
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then you do the number that appears the most like 3*3 is the most for the 3
2*3*3*5*7*41
2*3=6*3=18*5=90*7=630*41=25,830
To conclude the answer is 25,830
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How many solutions does a triangle with side lengths a = 4, A = 112º and b =<br>9 have?​
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Step-by-step explanation:

Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.

This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":

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