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kodGreya [7K]
3 years ago
10

Solve the following

Mathematics
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

1. log_{10} \: 35 - \: log_{10}17.5

Answer: 0.331 \: aprox. [/tex]

2. log_{3} \: 27 + 2 log_{3} \: 9 - log_{3} \: 54

Answer: -9 log_{3}

Explanation:

log_{10}35 -  log_{10}17.5 \\ =   log_ \frac{35}{17.5}  \\    = log_{10}0.5 \\   =  log_{5} -  log_{10}10 \\  =  log_{5 - 1} \\ = 0.669 - 1  \\  = 0.331 \: aprox.

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The area of a regular octagon is 25 cm2. What is the area of a regular octagon with sides four times as large?
Scorpion4ik [409]
Regular polygon area = n*side^2 / (4 * tan (180/n))
where "n" is number of sides
The formula is dependent on the side^2 term,
So, if we have an octagon that has sides 4 times as large, that means the area will be sixteen times larger.
side^2 = 4^2 = 16
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400 square centimeters.

Source:
http://www.1728.org/polygon.htm


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3 years ago
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