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3 years ago

11

Nilton acude a una institución privada que ofrece una tasa de interés del 0,5% mensual por el dinero que deposites, a un plazo f

ijo de 4 años. Nilton decide depositar su dinero que asciende a S/25 000. Al cabo del tiempo fijado, retira el 80%, ¿cuánto es lo que le queda en el banco?

1 answer:

jeka57 [31]3 years ago

3 0

Answer:

hey, i might help in english?

Step-by-step explanation:

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2x-1<br> Hahahahahhaahhahahahahahahhahaha

sweet-ann [11.9K]

Answer:

x=1/2

Step-by-step explanation:

Set up the equation: 2x-1=0

Add one to both sides. 2x=1

Divide two by both sides: x=1/2

Therefore, x =1/2, or .5

4 0

3 years ago

Read 2 more answers

A group of friends were working on a student film. They spent all their budget on props and costumes. They spent $243 on props,

SVETLANKA909090 [29]

Answer:

The total budget for their student film was $540

Step-by-step explanation:

The total percentage of any quantity is 100%

∵ A group of friends was working on a student film

∵ They spent all their budget on props and costumes

∴ The total budget of the props and costumes = 100%

∵ They spent $243 on props

∵ They spent 55% of the total budget on costumes

→ Find the percentage of the props

∴ The percentage of the props = 100% - 55%

∴ The percentage of the props of the total budget = 45%

→ That means 45% of the total budget = 243

∵ 45% × total budget = 243

→ Change the percent to a number by divide it by 100

∵ 45% = 45 ÷ 100 = 0.45

∴ 0.45 × total budget = 243

→ Divide both sides by 0.45

∴ The total budget = 540

∴ The total budget for their student film was $540

4 0

3 years ago

Read 2 more answers

Each tire on your bicycle has a diameter of 26 inches.About how far will you travel when the tires make on complete revolution?

ValentinkaMS [17]

Circumference of a circle is an equation

c = (pie) x d or ........ c = 2(pie) × r
c = 3.14 × d or ...... c = 2(3.14) x r

d is the diameter and r is radius

c = (3.14) x 26
c = 81.64 in.

6 0

3 years ago

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Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

3 years ago

If n = 4, all of the following expressions are equivalent except

Lorico [155]

Answer:

n to the power of -2

Step-by-step explanation:

i counted all the others and this is the only one that doesn't add up to 16. the last answer is -16 not 16 so there you go.

8 0

3 years ago