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Sindrei [870]
3 years ago
7

The figure below shows a shaded region and a non-shaded region. Angles in the figure that appear to be right angles are right an

gles.
Picture

What is the area, in square feet, of the shaded region?

What is the area, in square feet, of the non-shaded region?

Mathematics
2 answers:
Naddika [18.5K]3 years ago
3 0

Answer:

the shaded area is 26, the non-shaded area 16

Step-by-step explanation:

The red shaded lines had numbers as well so I add all of them up.

The non-shaded lines didn't have a number, but the bottom had the same length of the top line so therefore your answer is 26 for Shaded, and 16 for non-shaded.

klasskru [66]3 years ago
3 0
<h3><u>Revising the formulas.</u></h3>

<u>Let's divide the shape into 1 triangle and 2 rectangles.</u>

  • => Area of triangle = 1/2 x base x altitude
  • => Area of rectangle = Length x Breadth
<h3><u>Finding the area of the triangle</u></h3>
  • 1/2 x 10 x 3 = Area of triangle
  • => 1 x 5 x 3 = Area of triangle
  • => 15 feet² = Area of triangle
<h3><u>Finding the area of the SMALL rectangles</u></h3>
  • (10 x 1) + (8 x 2) = Area of the small rectangles
  • => 10 + 16 = Area of the small rectangles
  • => 26 feet² = Area of the small rectangles
<h3><u>Finding the area of the figure</u></h3>
  • <u>15 + 26 = Area of figure</u>
  • => 41 feet² = Area of figure
<h3><u>Finding the area of the BIG rectangle</u></h3>
  • 8 x 16 = Area of BIG rectangle
  • => 128 feet² = Area of BIG rectangle
<h3><u>Finding the area of the unshaded region</u></h3>
  • 128 - 41 = Area of unshaded region
  • => 87 feet² = Area of unshaded region
<h3><u>Answers:</u></h3>
  • Part-1: 41 feet²
  • Part-2: 87 feet²
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Step-by-step explanation:

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vfiekz [6]

Answer:

a) For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

b) From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that sin (\pi/3) = \frac{\sqrt{3}}{2}

And for this case since we ar einterested on -\frac{\pi}{3} and we know that the if we are below the y axis the sine would be negative then:

sin (-\pi/3) = -\frac{\sqrt{3}}{2}

Part b

From definition we can use the fact that tan x= \frac{sin x}{cos x} and we got this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}

We can use the notabl angle \pi/4 and we know that :

sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}

Then we know that 5\pi/4 correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1

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