Step-by-step explanation:
y=6+4x, as equation (iii)
=> -5x-(6+4x)=21
=> -5x-6-4x=21
=> -5x-4x-6=21
=> -9x-6=21
=> -9x=21+6
=> -9x=27
x= -3, by dividing both sides by -9
So, by inserting x in the first equation,
=> -4(-3)+y=6
=> 12+y=6
=> y=6-12
=> y= -6.
Therefore, x= -3 and y= -6
Answer:
y=2x+1, assuming my change in the reported data was correct.
Step-by-step explanation:
The data for x had one more entry than the values for y. I removed the second "0" so that the x and y points line up, as shown in the attached image. The data indicate a straight line, with a slope of 2 (y increases by 2 for every x increase of 1). The y-intercept is 1, as per the first data point (0,1).
Answer:
6
2
+
8
−
2
5
=
−
3
6a^{2}+8a-25=-3
6
2
+
8
−
2
5
−
(
−
3
)
=
0
Step-by-step explanation:
0/3
Answer:
129.8 approximately
Step-by-step explanation:
So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.
So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.
My math is case sensitive.
X is the angle opposite to the side x.
Law of cosines formula is:

So we are looking for X.
We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).



Subtract 80 on both sides:


Divide both sides by -64:

Now do the inverse of cosine of both sides or just arccos( )
[these are same thing]

Time for the calculator:
X=129.8 approximately