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Svetlanka [38]
3 years ago
13

Jim ordered a sports drink and three slices of pizza for $8.50. His friend ordered two sports drinks and two slices of pizza for

$8.00.
Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

total is 16.50

Step-by-step explanation:

add 8.50+8.00

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Solve 9,168 ÷ 24 using standard algorithm quick!
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382

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I can give you straight up answer.

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2 years ago
Simplify 4+2 squared
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5 0
3 years ago
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Find all the integers,b, that make up the trinomial x2 + bx + 10 factorable.
KonstantinChe [14]

By the fundamental theorem of algebra, we can write

x^2+bx+10=(x-r_1)(x-r_2)

Expanding the right hand side, we get

x^2+bx+10=x^2-(r_1+r_2)x+r_1r_2\implies\begin{cases}r_1+r_2=-b\\r_1r_2=10\end{cases}

We want b to be an integer, which means r_1,r_2 must also be integers. This means r_1,r_2 must be factors of 10. There are several possibilities:

r_1=\pm10,r_2=\pm1\implies b=-(10+1)=-11\text{ or }b=-(-10-1)=11

r_1=\pm5,r_2=\pm2\implies b=-(5+2)=-7\text{ or }b=-(-5-2)=7

So there are 4 possible values for b: -11, -7, 7, and 11.

7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
tangare [24]

Answer:

<h3>The given expression can be written in the form q(x)+\frac{r(x)}{b(x)} as (2x^2-x+3)+\frac{0}{x-3} where  q(x)=2x^2-x+3 , r(x)=0 and b(x)=x-3</h3>

Step-by-step explanation:

Given rational expression is \frac{2x^3-7x^2+6x-9}{x-3}

<h3>To rewrite the given rational expression in the given form  and match their correct expressions:</h3>

Rewrite the given rational expression \frac{2x^3-7x^2+6x-9}{x-3} in the form of q(x)+\frac{r(x)}{b(x)} where q(x) is the quotient, r(x) is the remainder and b(x) is the divisor.

<h3>Now solve the given expression by using Synthetic division, we get</h3>

Since x-3 is a factor for 2x^3-7x^2+6x-9

<h3>Therefore b(x)=x-3</h3>

3_|   2     -7     6     -9

       0      6    -3      9

   ------------------------------------

      2      -1       3      0

  ------------------------------------

Therefore we have quadratic equation 2x^2-x+3=0

<h3>q(x)=2x^2-x+3</h3><h3>Remainder is 0</h3><h3>Therefore r(x)=0</h3>

Therefore we can write in the form as (2x^2-x+3)+\frac{0}{x-3}

It is in the form of q(x)+\frac{r(x)}{b(x)}

<h3>Therefore the given expression can be written in the form q(x)+\frac{r(x)}{b(x)} as (2x^2-x+3)+\frac{0}{x-3} where  q(x)=2x^2-x+3 , r(x)=0 and b(x)=x-3</h3>

3 0
2 years ago
Read 2 more answers
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