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Kamila [148]
3 years ago
5

monica tiene 6/10kg de dulces con los cuales llena 1/4 de una bolsa de celofn ¿cual es la capacidad de la bolsa?

Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0
The question in English
<span>Monica has 6 /10 kg of candy with which she fills 1/4 of a cellophane bag. What is the capacity of the bag?
</span>
we know that
6/10---------> 0.60
1/4----------> 0.25------> 25%

if 25% of a cellophane bag---------------> has a 0.60 kg of candy
100%-----------------------------------------> X
X=100*0.60/25--------> X=2.4 kg

the answer is
2.4 kg


the answer in Spanish

Sabemos que
6/10---------> 0.60
1/4----------> 0.25------> 25%

if 25% de la bolsa de celofan---------------> se llena con 0.60 kg de dulces
100% de la bolsa----------------------------------------->se llenara con  X kg 
X=100*0.60/25--------> X=2.4 kg

La respuesta es
2.4 kg
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35. The fraction 21/2 or the decimal 10.5
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37. Segment AB
38. The values are x = 6; y = 2
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41. C) 108 degrees
42. The value of x is x = 70
43. The segment WY is 24 units long
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Work Shown:
Problem 33) 
RS = ST, means that the vertex angle is at angle S
Angle S = 44
Angle R = x, angle T = x are the base angles
R+S+T = 180
x+44+x = 180
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So angle R is 68 degrees
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Problem 35) 
Angle A = angle H
Angle B = angle I
Angle C = angle J
A = 97
B = 4x+4
C = J = 37
A+B+C = 180
97+4x+4+37 = 180
4x+138 = 180
4x+138-138 = 180-138
4x = 42
4x/4 = 42/4
x = 21/2
x = 10.5
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Problem 36) 
GD is the median of triangle ACG. It stretches from the vertex G to point D. Point D is the midpoint of segment AC
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Problem 37)
Segment AB is an altitude of triangle ACG. It is perpendicular to line CG (extend out segment CG) and it goes through vertex A.
-----------------
Problem 38) 
triangle LMN = triangle PQR
LM = PQ
MN = QR
LN = PR
Since LM = PQ, we can say 2x+3 = 5x-15. Let's solve for x
2x+3 = 5x-15
2x-5x = -15-3
-3x = -18
x = -18/(-3)
x = 6
Similarly, MN = QR, so 9 = 3y+3
Solve for y
9 = 3y+3
3y+3 = 9
3y+3-3 = 9-3
3y = 6
3y/3 = 6/3
y = 2
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Problem 40) 
The remote interior angles (2x and 21) add up to the exterior angle (3x-8)
2x+21 = 3x-8
2x-3x = -8-21
-x = -29
x = 29
-----------------
Problem 41) 
For any quadrilateral, the four angles always add to 360 degrees
J+K+L+M = 360
3x+45+2x+45 = 360
5x+90 = 360
5x+90-90 = 360-90
5x = 270
5x/5 = 270/5
x = 54
Use this to find L
L = 2x
L = 2*54
L = 108
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Problem 42) 
The adjacent or consecutive angles are supplementary. They add to 180 degrees
K+N = 180
2x+40 = 180
2x+40-40 = 180-40
2x = 140
2x/2 = 140/2
x = 70
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Problem 43) 
All sides of the rhombus are congruent, so WX = WZ.
Triangle WPZ is a right triangle (right angle at point P).
Use the pythagorean theorem to find PW
a^2+b^2 = c^2
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(PW)^2+256 = 400
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(PW)^2 = 144
PW = sqrt(144)
PW = 12
WY = 2*PW
WY = 2*12
WY = 24
3 0
3 years ago
[XTRA POINTS] Number 32 looks easy, but i cant get it...
Tju [1.3M]

Diameter = 6, so length of diagonal = 6

a² + b² = c²

a = x, b = x, and c = 6

x² + x² = 6²

2x² = 36

x² = 18

x = √18

x ≈ 4.2426

x ≈   4.2 in.


Hope this helps you!

Have an amazing day :)

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
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