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Marina86 [1]
3 years ago
14

The circular play area has a diameter of 16 feet. There is a walkway that surrounds the play area and is 3 feet wide. What is th

e area of the walkway? Round your answer to the nearest whole foot?
Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

If you use 3.14 as an approximation for PI, the answer will be A) 179 sq. feet.

Step-by-step explanation:

The process to determine the area of the sidewalk is computed by figuring the area of the outer circle (Diameter = 16' + 3' + 3') and subtracting the area of the fountain (Diameter = 16') from that.

Area of Circle = PI times Radius squared

Outer circle radius = (22 ft /2) = 11 ft

Area of outer circle (includes fountain area too) = 3.14 x 11 x 11 = 379.94 ~ 380

Inner circle radius = (16 ft / 2) = 8 ft

Area of Fountain = 3.14 x 8 x 8 = 200.96 ~ 201

Area of sidewalk =  380 - 201 =  179

Read more on Brainly.com - brainly.com/question/11852368#readmore

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Factors of 28 and 44
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28= 1,2,4,7,14,28,   

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5 0
3 years ago
The radius of a circle is 20 cm. Find its area in terms of π π.
natulia [17]

Answer:

A = 400\pi cm^2

Step-by-step explanation:

Area of a circle is:

A = πr²

We are given a radius of 20 cm.

A = πr²

A = π(20)²

A = π400

<em>A = 400πcm²</em>

Hope this helps.

4 0
3 years ago
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babymother [125]

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Step-by-step explanation:

3 0
3 years ago
Answer this question please; number 5... show all work thank you
My name is Ann [436]

Answer:

rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour

Step-by-step explanation:

We will make a table of the trip there and back using the formula distance = rate x time

                 d              =            r       x       t

there

back

The distance there and back is 264 miles, so we can split that in half and put each half under d:

               d            =         r        x        t

there    132

back     132

It tells us that the trip there is with the wind and the trip back is against the wind:

           

              d           =        r         x        t

there     132        =    (r + w)

back      132       =     (r - w)

Finally, the trip there took 3 hours and the trip back took 6:

           

             d         =        r        *        t

there    132     =    (r + w)     *       3

back     132     =    (r - w)      *       6

There's the table.  Using the distance formula we have 2 equations that result from that info:

132 = 3(r + w)        and        132 = 6(r - w)

We are looking to solve for both r and w.  We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:

132 = 3r + 3w and

132 - 3w = 3r so

44 - w = r.  Subbing that into the second equation:

132 = 6(44 - w) - 6w and

132 = 264 - 6w - 6w and

-132 = -12w so

w = 11

Subbing w in to solve for r:

132 = 3r + 3(11) and

132 = 3r + 33 so

99 = 3r and

r = 33

7 0
3 years ago
Which of the following equations has the same solution as m-(-62) = 45?
prisoha [69]

Answer:

answer 45

Step-by-step explanation:

it is thr right answe

5 0
3 years ago
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