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Rom4ik [11]
4 years ago
7

Find the perimeter of the following shape, rounded to the nearest tenth:

Mathematics
2 answers:
Oksanka [162]4 years ago
6 0
I hope this helps you

mrs_skeptik [129]4 years ago
3 0
Perimeter of the shape is 2(AB) + 2(BC)

AB = sqrt((7 - 5)^2 + (3 - 5)^2) = sqrt(2^2 + (-2)^2) = sqrt(4 + 4) = sqrt(8) = 2.83
BC = sqrt((3 - 7)^2 + (0 - 3)^2) = sqrt((-4)^2 + (-3)^2) = sqrt(16 + 9) = sqrt(25) = 5

Perimeter = 2(AB) + 2(BC) = 2(2.83) + 2(5) = 5.66 + 10 = 15.7
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3 years ago
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7 0
3 years ago
At Black Horse Junior School there were altogether 394 teachers and children. The teachers and the boys numbered 189, and the gi
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5 0
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The width of a rectangle is shown below:
Phoenix [80]
The difference between the y-coordinates is 7 units. If the area is to be 42 square units, the missing coordinates must be 42/7 = 6 units to the right of those shown.
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3 years ago
Help me please i don't know what this is ​
sesenic [268]

Answer:

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5 = 5/1

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3 years ago
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