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vova2212 [387]
3 years ago
11

I'm new to this Help please ???

Mathematics
1 answer:
Akimi4 [234]3 years ago
4 0
B involves direct variation. 

y and x are directly proportional.
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If f(x) = 8x2 + 4x - 12. Find f(2)<br> f(2)=
posledela

Answer:

f(2) = 28

Step-by-step explanation:

\rm f(x) = 8 {x}^{2}  + 4x - 12

\rm Evaluate \:  8 x^2 + 4 x - 12 \:  where  \: x = 2: \\  \\  \rm \implies f(2) = 8 \times {2}^{2}  + 4 \times 2 - 12 \\  \\   \rm \implies f(2) = 8 \times 4 + 8 - 12 \\  \\   \rm \implies f(2) = 32 - 4 \\  \\   \rm \implies f(2) = 28

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3 years ago
Write a equation of a hyperbola given the foci and the asymptotes
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Solution:

The standard equation of a hyperbola is expressed as

\begin{gathered} \frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1\text{ \lparen parallel to the x-axis\rparen} \\ \frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ \lparen parallel to the y-axis\rparen} \end{gathered}

Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.

Thus, the equation will be expressed in the form:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1\text{ ----equation 1}

The asymptote of n hyperbola is expressed as

y=\pm\frac{a}{b}(x-h)+k

Given that the asymptotes are

y=\frac{3}{4}x\text{ and y=-}\frac{3}{4}x

This implies that

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To evaluate the value of h and k,

undefined

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ANSWER: 30

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NARA [144]

Answer: x=y-3    or            y=3+x

Step-by-step explanation:

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