Question

What are the solutions to the equation?

Answer 1

Answer:

x = −10 and x = 4

Step-by-step explanation:

We are given the following quadratic equation and we are to solve it to find the two solution for the variable x:

$x^2+6x=40$

Rearranging the equation by putting the constant on the same side as the variables to get:

$x^{2} +6x-40=0$

Now factorizing it to get:

$x^{2} -4x+10x-40=0\\\\x(x-4)+10(x-4)=0\\\\(x+10)(x-4)=0\\\\x= -10, x= 4$

Therefore, the solution to the given quadratic equation $x^2+6x=40$ are x = −10 and x = 4.

Answer 2

Answer:

x = −10 and x = 4

Step-by-step explanation:

x2 + 6x = 40

Subtract 40 from each side

x^2 + 6x -40 =0

Factor,  what 2 numbers multiply to -40 and add to 6

10 * -4 = -40    10+-4 = 6

(x+10) (x-4) = 0

Using the zero product property

x+10 =0     x-4=0

x=-10    x=4