Answer:
I don't understand the instructions, but I'll answer the question in the picture.
The angle next to 52 is vertical to y, so, 90-52=y.
Thus, y=38
Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
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Answer:
The converse of the Pythagorean theorem states that if the square of one side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle.
