Answer:
None of the transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.
Explanation:
Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy. If it is in the second energy level, it must have -3.4 eV of energy and so on.
If the electron wants to jump from the first energy level, n = 1, to the second energy level n = 2. The second energy level has higher energy than the first, so to move from n = 1 to n = 2, the electron needs to gain energy. It needs to gain (-3.4) - (-13.6) = 10.2 eV of energy to be excited to the second energy level.
The step from the second energy level to the third is much smaller. It takes only 1.89 eV of energy for this excitation to take place. It takes even less energy to excite electrons in hydrogen from the third energy level to the fourth, and even less from the fourth to the fifth.
None of these transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.
Yes. If an object would be vertical, it would most likely have potential energy due to gravity.
B) The 6 kg ball has a greater force of gravity exerted on it
Explanation:
The force of gravity on an object near the Earth's surface, also called weight of the object, is given by the equation
where
m is the mass of the object
g is the acceleration due to gravity
In this problem, we have two balls of mass 4 kg and 6 kg. From the equation above, we see that the force of gravity is directly proportional to the mass of the object. Therefore, since the value of g is equal for the two balls (they are both at the same location), this means that the force of gravity will be stronger for the ball with larger mass, therefore for the ball of 6 kg. So the correct statement is
B) The 6 kg ball has a greater force of gravity exerted on it.
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Answer:
15.64 KN
Explanation:
mass of the elevator cab with a single occupant= 2300 kg
acceleration relative to the cab = 6.80 m/s^2
acceleration of the coin relative to the cab in the opposite direction of motion of cab so we can consider it as a= -6.80 m/s^2
The acceleration of elevator cab relative to the ground
now we can say that
=-6.80+ a_{eg}= -9.8
[tex]a_{eg}=-9.8+6.80=-3.8
The forces that act on elevator cab are tension and gravitational, applying newtons second law
T- mg= ma_{eg}
Then the tension in the cable is
T= 2300(-3.8)+2300×9.8= 15640 N= 15.64 KN
therefore tension in the string will be 15.64 KN