Answer: Mercury is rarely used in thermometers that take body temperatures because it is toxic, accidentally if by any chance a thermometer breaks orleaky, mercury gets inside body and can cause harm.
Explanation:
1 the mantle is the layer
If you or any else needs the answer for this it is C. +1.11 m/s.
Answer:
The ball land at 3.00 m.
Explanation:
Given that,
Speed = 40 m/s
Angle = 35°
Height h = 1 m
Height of fence h'= 12 m
We need to calculate the horizontal velocity
Using formula of horizontal velocity
![V_{x}=V_{i}\cos\theta](https://tex.z-dn.net/?f=V_%7Bx%7D%3DV_%7Bi%7D%5Ccos%5Ctheta)
![V_{x}=40\times\cos35](https://tex.z-dn.net/?f=V_%7Bx%7D%3D40%5Ctimes%5Ccos35)
![V_{x}=32.76\ m/s](https://tex.z-dn.net/?f=V_%7Bx%7D%3D32.76%5C%20m%2Fs)
We need to calculate the time
Using formula of time
![t = \dfrac{d}{v}](https://tex.z-dn.net/?f=t%20%3D%20%5Cdfrac%7Bd%7D%7Bv%7D)
![t=\dfrac{130}{32.76}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B130%7D%7B32.76%7D)
![t=3.96\ sec](https://tex.z-dn.net/?f=t%3D3.96%5C%20sec)
We need to calculate the vertical velocity
![v_{y}=v_{y}\sin\theta](https://tex.z-dn.net/?f=v_%7By%7D%3Dv_%7By%7D%5Csin%5Ctheta)
![v_{y}=40\times\sin35](https://tex.z-dn.net/?f=v_%7By%7D%3D40%5Ctimes%5Csin35)
![v_{y}=22.94\ m/s](https://tex.z-dn.net/?f=v_%7By%7D%3D22.94%5C%20m%2Fs)
We need to calculate the vertical position
Using formula of distance
![y(t)=y_{0}+V_{i}t+\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=y%28t%29%3Dy_%7B0%7D%2BV_%7Bi%7Dt%2B%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
Put the value into the formula
![y(3.96)=1+22.94\times3.96+\dfrac{1}{2}\times(-9.8)\times(3.96)^2](https://tex.z-dn.net/?f=y%283.96%29%3D1%2B22.94%5Ctimes3.96%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%28-9.8%29%5Ctimes%283.96%29%5E2)
![y(3.96)=15.00\ m](https://tex.z-dn.net/?f=y%283.96%29%3D15.00%5C%20m)
We need to calculate the distance
![s = y-h'](https://tex.z-dn.net/?f=s%20%3D%20y-h%27)
![s=15.00-12](https://tex.z-dn.net/?f=s%3D15.00-12)
![s=3.00\ m](https://tex.z-dn.net/?f=s%3D3.00%5C%20m)
Hence, The ball land at 3.00 m.
Answer:
83%
Explanation:
On the surface, the weight is:
W = GMm / R²
where G is the gravitational constant, M is the mass of the Earth, m is the mass of the shuttle, and R is the radius of the Earth.
In orbit, the weight is:
w = GMm / (R+h)²
where h is the height of the shuttle above the surface of the Earth.
The ratio is:
w/W = R² / (R+h)²
w/W = (R / (R+h))²
Given that R = 6.4×10⁶ m and h = 6.3×10⁵ m:
w/W = (6.4×10⁶ / 7.03×10⁶)²
w/W = 0.83
The shuttle in orbit retains 83% of its weight on Earth.