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f′(x)=2∗(8x(2−1))+1∗11x(1−1)
which is
f′(x)=16x+11
then let
x = 7 gives us
f′(7)=123
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Answer:
6
Step-by-step explanation:
You need to divide it.Then you get 18 divided by 3.Which is 6
Answer:
The ordinate of B exceeds the ordinate of A by 7
Step-by-step explanation:
Let
A(x1,y1),B(x2,y2)
where
x1 is the abscissa of A
x2 is the abscissa of B
y1 is the ordinate of A
y2 is the ordinate of B
we know that


so
-----> equation A
----> equation B
substitute equation B in equation A
therefore
The ordinate of B exceeds the ordinate of A by 7