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abruzzese [7]
3 years ago
12

An airplane flew with the wind for 2.5 hours and returned the same distance against the wind in 3.5 hours. If the cruising speed

of the plane was a constant 360 mph in air, how fast was the wind blowing
Mathematics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

60 miles per hour.

Step-by-step explanation:

Let r represent speed of wind blowing in miles per hour.          

We have been given that the cruising speed of the plane was a constant 360 mph in air. The speed of the plane is the direction of wind would be 360+r.

The speed of the plane is the opposite direction of wind would be 360-r.

\text{Distance}=\text{Speed}\times \text{Time}

Distance covered in the direction of wind would be 2.5(360+r).

Distance covered in the opposite direction of wind would be 3.5(360-r).

Since both distances are same, so we will get:

2.5(360+r)=3.5(360-r)

900+2.5r=1260-3.5r

900-900+2.5r+3.5r=1260-900-3.5r+3.5r

6r=360

\frac{6r}{6}=\frac{360}{6}

r=60

Therefore, the wind is blowing at a rate of 60 miles per hour.

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