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2 years ago

S is the midpoint of RT. If RS = 4x - 3 and RT = 6x - 4, what’s the value of ST?

Mathematics

1 answer:

Georgia [21]2 years ago

7 0

Answer:

R__S__T

RT = RS + ST

6x – 4 = ( 4x – 3) + ST

(6x – 4 ) – ( 4x – 3 ) = ST

(6x – 4 ) +( – 4x + 3 ) = ST

2x – 1 = ST

ST = 2x – 1

RS=ST

4x – 3 = 2x – 1

4x – 2x = – 1 +3

2x = 2

x= 2/2

x =1

ST = 2x – 1 = 2(1) – 1 =2 ‐ 1 = 1

ST = 1

I hope I helped you^_^

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$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

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The formula of a distance between a point and a line:

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$\dfrac{2}{3}x-y+b=0$ |multiply both sides by 3

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