S is the midpoint of RT.
If RS = 4x - 3 and RT = 6x - 4,
what’s the value of ST?
1 answer:
Answer:
R__S__T
RT = RS + ST
6x – 4 = ( 4x – 3) + ST
(6x – 4 ) – ( 4x – 3 ) = ST
(6x – 4 ) +( – 4x + 3 ) = ST
2x – 1 = ST
ST = 2x – 1
RS=ST
4x – 3 = 2x – 1
4x – 2x = – 1 +3
2x = 2
x= 2/2
x =1
ST = 2x – 1 = 2(1) – 1 =2 ‐ 1 = 1
ST = 1
I hope I helped you^_^
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