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AURORKA [14]
3 years ago
15

Please help! I dont understand! Thank you

Mathematics
1 answer:
Digiron [165]3 years ago
6 0

QUESTION A

The given inequality is  

x-1\:>\:5

Add 1 to both sides of the inequality to obtain;

x\:>\:5+1

x\:>\:6

Answer: 2. x\:>\:6, open dot at 6 and shaded to the right.(A)

QUESTION B.

The given inequality is 2x \le 6.

Divide both sides by 2;

x \le \frac{6}{2}.

x \le 3.

Answer: 5. x \le 3, closed dot at 3 and shaded to the left(B).

QUESTION C

The given inequality is x-7\:>\:-4

Add 7 to both sides to get;

x\:>\:-4+7

\Rightarrow x\:>\:3

Answer: 7. x\:>\:3, open dot at 3 and shaded to the right.(C)

QUESTION D

We want to solve;

-2x \:

Divide through by -2 and reverse the inequality sign;

x \:>\:\frac{6}{-2}

x \:>\:-3

Answer; 3. x \:>\:-3 Open dot at -3 and shaded to the right. (D)

QUESTION E

We have  

4\:

Divide through by -4 and reverse the sign.

\frac{4}{-4}\:>\:x

-1\:>\:x

or

x\:

Answer: 6. x\: open dot at -1, and shaded to the left(E)

QUESTION F

The given inequality is -2x+3\:

Add -3 to both sides to get;

-2x\:

-2x\:

Divide both sides of the inequality by -2 and reverse the sign;

x\:>\:5

Answer:9. x\:>\:5, open dot at 5 and shaded to the right(F)

QUESTION G

The given  inequality is

5x+1\ge11

5x\ge11-1

5x\ge10

Divide by 5

x\ge2

Answer ; 10. x\ge2, closed dot at 2 and shaded to the right(G)

QUESTION H

We have 3(x+4)\:>\:8x-6

Expand the bracket to get;

3x+12\:>\:8x-6

Group similar terms to get;

3x-8x\:>\:-6-12

Simplify

-5x\:>\:-18

Divide through by -5 and reverse the sign;

x\:

Answer: 1. x\: Open dot at 18/5 and shaded to the left(H)

QUESTION I

We have -3x+4\:.

-3x+x\:

-2x\:

Divide by -2 and reverse the sign;

x\:>\:1

Answer: 8. x\:>\:1, open dot at 1 and shaded  to the right(I)

J. The given inequality -2(x-4)\:>\:5-(x+2)

Expand the bracket to get;

-2x+8\:>\:5-x-2

Group like terms to get;

-2x+x\:>\:5-2-8

-x\:>\:-5

Divide by -1 and reverse the sign to get;

x\:

Answer; 4. x\:, open dot at 5 and shaded to the left.(J)

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