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4 years ago

NEED HELP PLEASE!! WILL GIVE A MEDAL!!

1 answer:

8 0

Hello,

Part A:

f(2)=4*2²=16
f(1)=4*2^1=8
2-1=1
(f(2)-f(1))/(2-1)=(16-8)/1=8 ; r_1=8

f(3)=4*2^3=32
f(4)=4*2^4=64
(f(4)-f(3))/(4-3)=(64-32)/1=32 ; r_2=32

Part B:
r_2=32=4*8=4*r_1

Explainations:

(4*2^2-4*2^1)/(2-1)=4*2^1(2-1)=4*2
(4*2^4-4*2^3)/(4-3)=4*2^3*(2-1)=4*8=(4*2)*4

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