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Morgarella [4.7K]
3 years ago
7

Multiply and Simplify (x-4)(-5x - 6)

Mathematics
1 answer:
zmey [24]3 years ago
5 0

Answer:

-5x^2 +14x +24

Step-by-step explanation:

(x-4)(-5x - 6)

FOIL

first : x*-5x = -5x^2

outer : -6x

inner: -4*-5x = 20x

last: -4*-6 = 24

Add them together

-5x^2 -6x+20x +24

-5x^2 +14x +24

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Pls ASAP help me with number 14
attashe74 [19]

Answer:

D. 19

Step-by-step explanation:

because they are parallel bases you can compare

63/57 = 21/x

x = 19

4 0
3 years ago
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Ned created a video that was originally 40 minutes
Zanzabum

Answer:

36.8 minutes or 36 minutes 48 seconds

Step-by-step explanation:

8 percent of 40 is 3.2

(.08 times 40)

40 minus 3.2 is 36.8 :)

(.8 times 60 is 48)

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3 years ago
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What’s that precent 250 of 275
tester [92]

Answer:

Percent 250 of 275 is 90.9%

Step-by-step explanation:

We have to find 250 is what percent of 275.

Let X be the percentage, then

=> X =  \frac{250}{275} \times 100

Now simplyfying the above relation we get

=> X =  0.909\times 100

=> => X = 90.9 %

Hence 250 is 90.9% of 275

5 0
3 years ago
Solve this inequality. 7.2-3w<4.5
zlopas [31]

Answer:

w>0.9

Step-by-step explanation:

7.2-3w<4.5

-7.2       -7.2

-3w<-2.7

/-3    /-3

w>0.9

The inequality switches when divided by a negative.

-hope it helps

8 0
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A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a lon
algol [13]

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis:\mu_{men} \leq \mu_{women}

Alternative hypothesis:\mu_{men} > \mu_{women}

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is z_{calc}

Since is a right tailed test test the p value would be:

p_v =P(Z>z_{calc})=0.225

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that p_v >\alpha

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

8 0
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