Question

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Answer 1

Answer: D

Step-by-step explanation:

$f(x) = \dfrac{2}{x-1}-3$

The vertical asymptote is the restriction on the x-value.  Since the denominator cannot be equal to zero, then x - 1 ≠ 0 →  x ≠ 1.     So, the vertical asymptote is: x = 1  

The horizontal asymptote is the restriction on the y-value.  Since the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y = 0.  However, there is a vertical shift of 3 units down so the horizontal asymptote is: y = -3

The only graph that has these asymptotes is the last one, which I call graph D.