What is the equation of the line that passes through (-3,-1 ) and has a slope of 3/5

Mathematics

1 answer:

vfiekz [6]3 years ago

7 0

The point-slope form:

$y-y_1=m(x-x_1)$

We have the point (-3, -1) and the slope m = 3/5. Substitute:

$y-(-1)=\dfrac{3}{5}(x-(-3))\\\\y+1=\dfrac{3}{5}(x+3)\qquad\text{use distributive property}\\\\y+1=\dfrac{3}{5}x+\dfrac{9}{5}\qqua\text{subtract 1 from both sides}\\\\y=\dfrac{3}{5}x+\dfrac{4}{5}\qquad\text{multiply both sides by 5}\\\\5y=3x+4\qquad\text{subtract 3x from both sides}\\\\-3x+5y=4\qquad\text{change the signs}\\\\3x-5y=-4$

Answer:

point-slope form: y + 1 = 3/5(x + 3)

slope-intercept form: y = 3/5x + 4/5

standard form: 3x - 5y = -4

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Read 2 more answers

What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

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Answer: The answer is (D) $y-1=\dfrac{3}{2}(x+3).$

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The points (-2, -4) and (2, 2) lie on the line in the graph, so its slope will be

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