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ivolga24 [154]
4 years ago
15

2-n in a written expression

Mathematics
2 answers:
ololo11 [35]4 years ago
7 0
It is... 2 taken away from n
Vika [28.1K]4 years ago
6 0
2 x n................
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Solve for x and y<br><br> Please help I forgot what I needed to do!
Nookie1986 [14]
The x is the part of y and you have to multiply 1+1 lol
7 0
1 year ago
An order is written for 1200 adult weight 164 pounds and is 5/9 all with a BSA of 1.9 m to the physician ordered o n c o v i n 2
Kaylis [27]

Answer:

The volume per dose that the patient should receive is 3.8 ml

Step-by-step explanation:

The physician ordered oncovin 2 mg/m² for chemotherapy treatment of a malignant tumor.

The adult's BSA (Body surface area) = 1.9m²

Hence, the amount of oncovin needed based on his body weight is:

2mg/1 m² = x mg/1.9m²

Cross Multiply

x mg = 2mg × 1.9

x = 3.8mg

We are told , oncovin is supplied:1 mg/ml

Hence:

This means

1 mg = 1 ml

3.8 mg = x ml

Cross Multiply

x ml = 3.8 ml

The volume per dose that the patient should receive is 3.8 ml

5 0
3 years ago
Suppose that a company prints baseball cards. They claim that 30% of the cards feature rookies, 60% feature veterans, and 10% fe
liraira [26]

Answer:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

Step-by-step explanation:

On this case we need to apply a Chi squared goodness of fit test, and the correct system of hypothesis would be:

H0: The distribution of players featured on the cards is 0.30 rookies, 0.60 veterans, and 0.10 All-Stars.

Ha: At least one of the proportions in the null hypothesis is false.

And in order to test it we need to have observed and expected values. On this case we  can calculate the Expected values like this

E_{rookies}=50*0.3=15

E_{veterans}=50*0.6=30

E_{All stars}=50*0.1=5

The observed values are not provided. The statistic on this case is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i) -E_i}{E_i}

And this statistic follows a chi square distribution with k-1 degrees of freedom on this case k=3, since we have 3 groups.

We can calculate the p valu like this:

P(\chi^2 > \chi^2_{calculated})=p_v

And if the p value it's higher than the significance level we FAIL to reject the null hypothesis. In other case we reject the null hypothesis.

5 0
3 years ago
Product of 11 ft * 825 ft
dmitriy555 [2]
The Answer would be 9075 you could also just multiply it on the calculater

6 0
4 years ago
Read 2 more answers
Need help, please need help
Montano1993 [528]

Answer:

Step-by-step explanation:

thats your problem learn how to pay attention lol

4 0
3 years ago
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