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andriy [413]
4 years ago
8

Match the reasons with the statements given.

Mathematics
2 answers:
Llana [10]4 years ago
6 0

Answer:

1st corresponds to the 4th

2nd corresponds to the 1st

3rd corresponds to the 3rd

4th corresponds to the 2nd

5th corresponds to the 5th

Step-by-step explanation:

tia_tia [17]4 years ago
5 0

Answer:

1. \overline{RS}||\overline{AB}, \angle 1=\angle 2:  Given

2. \angle B=\angle 1: If lines ||, corresponding \angle 's  are =.

3. \angle A=\angle 2: If lines ||, alternate interior \angle 's are =.

4. \angle A=\angle B: Substitution.

5. RB=RA: If two \angle 's of a triangle are =, sides opposite are =.

Step-by-step explanation:

We have been given a two column proof and we are asked to match the correct reason with each statement.

We have been given that line segment RS is parallel to line segment AB and measure of angle 1 is equal to measure of angle 2.

1. \overline{RS}||\overline{AB}, \angle 1=\angle 2:  Given

We know corresponding angles of two parallel lines are equal, therefore, measure of angle B is equal to measure of angle 1.

2. \angle B=\angle 1: If lines ||, corresponding \angle 's  are =.

We know that alternate interior angles of two parallel lines are equal. We can see that angle A and angle 2 are alternate interior angles of parallel lines RS and AB, therefore, measure of angle A is equal to measure of angle 2.

3. \angle A=\angle 2: If lines ||, alternate interior \angle 's are =.

We have been given that \angle 1=\angle 2. We figured that \angle A=\angle 2 and \angle B=\angle 1. By substitution property of equality \angle A=\angle B.

4. \angle A=\angle B: Substitution.

We know that if two angles of a triangle are equal, then the sides opposite to these angles are also equal. We can see that side RA is opposite side of angle B and side RB is opposite side of angle A.

Since \angle A=\angle B, then side RB=RA.

5. RB=RA: If two \angle 's of a triangle are =, sides opposite are =.

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The ratio is 3 to 1, or 3:1


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3 years ago
Please Answer Quick 70 Points !
Kipish [7]

Answer:

The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true

The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false

Step-by-step explanation:

we have

2x-y=-5 -----> First equation

x+3y=22 -----> Second equation

Solve the system of equations by graphing

Remember that the solution of the system is the intersection point both graphs

The solution is the point (1,7)

The ordered pair (7,19) lie on the first line, so is a solution of the first equation

see the attached figure

<u><em>Verify each statement</em></u>

case 1) The ordered pair (7, 19) is a solution to the first equation because it makes the first equation true

The statement is true

case 2) The ordered pair (7, 19) is a solution to the second equation because it makes the second equation true

The statement is false, because the ordered pair (7,19) not lie on the second line

case 3) The ordered pair (7, 19) is not a solution to the system because it makes at least one of the equations false

The statement is true

case 4) The ordered pair (7, 19) is a solution to the system because it makes both equations true

The statement is false,because it makes only the first equation true

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3 years ago
The Liter Is Associated with what English unit?
olchik [2.2K]
The <span>metric unit of weight.</span>
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bogdanovich [222]
Problem 1)

AC is only perpendicular to EF if angle ADE is 90 degrees

(angle ADE) + (angle DAE) + (angle AED) = 180
(angle ADE) + (44) + (48) = 180
(angle ADE) + 92 = 180
(angle ADE) + 92 - 92 = 180 - 92
angle ADE  = 88

Since angle ADE is actually 88 degrees, we do NOT have a right angle so we do NOT have a right triangle

Triangle AED is acute (all 3 angles are less than 90 degrees)

So because angle ADE is NOT 90 degrees, this means AC is NOT perpendicular to EF

-------------------------------------------------------------

Problem 2)

a) The center is (2,-3) 

The center is (h,k) and we can see that h = 2 and k = -3. It might help to write (x-2)^2+(y+3)^2 = 9 into (x-2)^2+(y-(-3))^2 = 3^3 then compare it to (x-h)^2 + (y-k)^2 = r^2

---------------------

b) The radius is 3 and the diameter is 6

From part a), we have (x-2)^2+(y-(-3))^2 = 3^3 matching (x-h)^2 + (y-k)^2 = r^2

where
h = 2
k = -3
r = 3

so, radius = r = 3
diameter = d = 2*r = 2*3 = 6

---------------------

c) The graph is shown in the image attachment. It is a circle with center point C = (2,-3) and radius r = 3.

Some points on the circle are

A = (2, 0)
B = (5, -3)
D = (2, -6)
E = (-1, -3)

Note how the distance from the center C to some point on the circle, say point B, is 3 units. In other words segment BC = 3.

6 0
3 years ago
The midpoint of AB is M(0,2). If the
otez555 [7]

Answer:

Step-by-step explanation:

(x+2)/2 = 0

x + 2 = 0

x = -2

(y - 3)/2 = 2

y - 3 = 4

y = 7

(-2, 7)

8 0
3 years ago
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