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Liula [17]
3 years ago
8

Find a number that is between 2/7 and 4/11 .

Mathematics
1 answer:
Furkat [3]3 years ago
7 0
To answer this problem, one way is to use the calculator and add directly the two numbers and get the average between the two. The answer is 25/77. We can also get this number by getting the LCM of the denominators which is 77. 2/7 is equal to 22/77 while 4/11 is equal to 28/77. 0.5*(22 +28) is equal to 25. Hence the answer is 25/77. 
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If angle 3 is 4x+1 and angle 4 is 7X+3. what are the measures of angle 3 and 4? ​
densk [106]
Answer:
3=13
4=31
Your welcome☺️
And don’t click on the links just report them bc it’s nothing but a hack
6 0
3 years ago
Is 85 prime or composite explain
forsale [732]
85 is a composite number because it has more than two factors.
85 factors are 1, 5, 17, 85

For example 5 is prime because it’s factors are only two of them
5 factors are 1, 5
8 0
3 years ago
Tereq pays $22.10 for 2.6 pounds of salmon. what is the price per pound of the salmon
astraxan [27]

Answer:

8.5 per pound

Step-by-step explanation:

22.10/2.6=8.5

hope this helps!!

3 0
3 years ago
Read 2 more answers
Using the Laws of exponents, simplify the following problem.
den301095 [7]
\frac{4 {}^{4} }{ {4}^{ - 8} ({4}^{ - 14}) } = \frac{4 {}^{4} }{ {4}^{ - 22 } }

(4^4)/(4^-22)
4^(4-(-22))
4^26


Follow my Account.
7 0
3 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
3 years ago
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