Answer:
Step-by-step explanation:
<u>Given the scale factor:</u>
Since the cylinders are similar, the other dimensions should have same scale factor of 1/3.
<u>The volumes are:</u>
<u>Ratio of volumes is the cube of the scale factor, as the volume is the product of 3 dimensions:</u>
- v/x = k³
- 67/x = (1/3)³
- x = 67*27
- x = 1809 cm³
X^2-2x -3 =0
a =1 b =-2 and c = -3
x = - (-2) +/- sqrt (-2)^2 - 4(1)(-3)
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2(1)
x = + 2 +/- sqrt [(4) - 4(-3)]
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2
x = +2 +/- sqrt [4 + 12]
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2
x = +2 +/- sqrt[16]
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2
x = +2 +/- (4)
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2
x = 2 + 4 or 2 -4
------- ------
2 2
x = 6/2 or -2/2
x = 3 or x = -1
Answer:
(a) 218.6 N
(b) 97.14 N
Step-by-step explanation:
When the system is in equilibrium, the net torque on the system is zero.
AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m
Let the centre of gravity of plank is at G.
AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m
(a) Let the reaction at C is R and at D is R'.
R + R' = 29 x 9.8 = 284.2 N ... (1)
Take the torque about C.
29 x 9.8 x CG = R' x GD
29 x 9.8 x 1 = R' x 1.3
R' = 218.6 N
(b) Take the torque about D.
6 x 9.8 x AD = R x CD
6 x 9.8 x (1.5 + 2.3) = R x 2.3
R = 97.14 N
Answer:
29 and 35
Step-by-step explanation:
x+y=64
x-y=6
Solve by substitution.
x=6+y
6+y+y=64
6+2y=64
y=29
Then plug in 29 for y.
x+29=64 ......35