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fredd [130]
3 years ago
7

Please help me find the area and perimeter of the trapezoid.

Mathematics
2 answers:
Xelga [282]3 years ago
7 0

Answer:

34 in

Step-by-step explanation:

A=a+b

2h=6+11

2·4=34

vlabodo [156]3 years ago
4 0
The answer is 34 inches , good luck on the resttt!!
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Rewrite the following expression using the properties of logarithms: log2z + 2log2z + 4log9y + 12log9x - 2log2y
Mashcka [7]

The rewritten form of the expression given in the task content in which case, the properties of the logarithm are used is; log2(z³/y²) + log9(y⁴x¹²).

<h3>What is the equivalent expression to the logarithmic expression given in the task content?</h3>

It follows from the task content that the logarithmic expression given in the task content is;

log2z + 2log2z + 4log9y + 12log9x - 2log2y

In which case, all terms are to their respective logarithmic bases.

Hence, it follows that; we have;

log2z³ - log2y² + log9y⁴ + log9x¹²

= log2(z³/y²) + log9(y⁴x¹²)

Read more on logarithm laws;

brainly.com/question/10208274

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4 0
2 years ago
How do you convert 15 feet to centimeters?
hram777 [196]
To convert 15 ft to centimeters you have to multiply 15 x 30.48, since 1 ft is 30.48 cms

So, if you want to calculate how many centimeters are 15 feet you can use this simple rule.

3 0
3 years ago
Read 2 more answers
How many cubes that have a edge length 1/2 inch are need to make a 1 cubic inch?
Nana76 [90]
The answer is D hope this helps
7 0
3 years ago
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Let f(x)=1/2x-3. Suppose you subtract 6 from the input of f to create a new function​ g, and then multiply the input of function
AlladinOne [14]

Answer: h(x)=2x-6

hope this helped

7 0
3 years ago
A thermometer is taken from a room where the temperature is 20°C to the outdoors, where the temperature is 3°C. After one minute
IrinaVladis [17]

Answer:

A. T=7.12°C; B. t=3.32min

Step-by-step explanation:

In order to find the answer we can use the Newton's law of cooling:

y(t)=y0e^{kt} where:

y0=initial temperature - room temperature

k=coefficients

t=time

Because the outdoors temperature is 3°C, the initial temperature is 20°C, and because the thermometer reads 11°C after 1min we have:

11=(20-3)e^{k*1}

ln(11/17)=k

-0.4353=k

A. Temperature after an extra minute.

y(2)=17e^{-0.4353*2}

y(2)=7.12 so the answer is 7.12°C

B. Time in order to read 4°C

4=17e^{-0.4353*t}

ln(4/17)/(-0.4353)=t}

3.32min=t

6 0
3 years ago
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