Answer:
91.6 km/h
Step-by-step explanation:
Let v = average speed of van = 65 km/h and v' = average speed of car. Let t be the time the car starts to move. The van started 35 minutes earlier at t' = (t + 35/60) h.
Since distance d = vt where v = velocity and t = time, the distance moved by the van d = vt' = v(t + 35/60) and that moved by the car is d' = v't.
Since the car catches up with the van after it had moved a distance of 130 km, d = d' = 130 km.
So d = v(t + 0.583)
Substituting d = 130 km and v = 65 km/h, we have
130 km = 65 km/h(t + 0.583)
130 km = (65t + 37.895 )km
subtracting 37.895 from both sides, we have
130 km - 37.895 km = 65t
92.105 = 65t
dividing both sides by 65, we have
t = 92.105/65
= 1.417 h
≅ 1.42 h
Since d = d' = v't,
v' = d'/t
= 130 km/1.42 h
= 91.55 km/h
≅ 91.6 km/h
So, the average speed of the car is 91.6 km/h
Answer:
7 units
Step-by-step explanation:
Calculate the distance using the absolute value function
| - 9 - (- 2) | = | - 9 + 2 | = | - 7 | = 7
or
| - 2 - (- 9) | = | - 2 + 9 | = | 7 | = 7
Answer:
I can't see them but whichever one is 157 is the correct angle
Step-by-step explanation:
Supplementary angles are angles that equal 180 degrees.
180 - 33 = 157
So whichever angle equals 157 degrees, that is the correct one
I think its is chemical energy orsolar energy.
4(2m-1)=16
8m-4=16
8m=20
m=20/8
=2.5
Hope this helps. Just ask if you need a better explanation.
