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qaws [65]
3 years ago
9

A web ad can be designed from four different colors, three font types, five sizes, three images, and five text phrases. A specif

ic design is randomly generated by the web server when you visit the site. Let A denote the event that the design color is red and let B denote the event that the font size is not the smallest one. Use the addition rilues to calculate the following probabilities:a. P(AuB)b. p(AuB')c. P(A'uB')
Mathematics
1 answer:
jeka57 [31]3 years ago
8 0

Answer:

a. 3/4

b. 1/2

c. 5/6

Step-by-step explanation:

From the question, We are given that:

4 different colours, 3 different font types, 5 sizes, 3 images, 5 text phrases.

If event A is the event that the design color is red, then:

P(A) = 1/4

P(A') = 1 - 1/4 = 3/4.

If event B is the event that the font size is not the smallest one, then:

P(B) = 2/3

P(B')= 1 - 2/3 = 1/3.

P(AnB) = 1/4 * 2/3 = 2/12=1/6

P(AnB')=1/4 * 1/3 = 1/12

P(A'nB') = 3/4 * 1/3=1/4

Solving the questions,

a. P(AuB) = P(A) + P(B) - P(AnB)

P(AuB) =(1/4) + (2/3) -(1/6)

P(AuB) = 9/12

P(AuB) = 3/4

b. P(AuB') = P(A) + P(B') - P(AnB')

P(AuB') = 1/4 + 1/3 - 1/12

P(AuB') = 6/12

P(AuB') = 1/2

c. P(A'uB') = P(A') + P(B') - P(A'nB')

P(A'uB') = 3/4 + 1/3 - 1/4

P(A'uB') = 10/12

P(A'uB')=5/6

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Step-by-step explanation:

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3 years ago
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Gnom [1K]

Answer:

See explanation below.

Step-by-step explanation:

Let's say,

x = number of tokens required to play one game of ping pong

y = number of token required play one game of pinball

Using the data given, the system of equations are:

\begin{bmatrix}9x+5y=29\\ 3x+y=7\end{bmatrix}

Solving the system of equations using substitution method will give us:

y=4\:\:\:,\:\:\:x=1

So, one game of ping pong required 1 token, whereas one game of pinball required 4 tokens.

3 0
4 years ago
A supplier of a certain car parts chain of stores wants to estimate the average length of time car owners plan to keep their car
____ [38]

Answer:

The 99% confidence interval for the average length of time all car owners plan to keep their cars is between 3.85 years and 10.55 years.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575*\frac{6.5}{\sqrt{25}} = 3.35

The lower end of the interval is the sample mean subtracted by M. So it is 7.2 - 3.35 = 3.85 years

The upper end of the interval is the sample mean added to M. So it is 7.2 + 3.35 = 10.55 years

The 99% confidence interval for the average length of time all car owners plan to keep their cars is between 3.85 years and 10.55 years.

7 0
3 years ago
Please help fast this has to be done by today can you also leave how you solved the problem thank you I will give points.
blagie [28]

Answer:

B

Step-by-step explanation:

  • First find the perdendicular slope (flip and change sign) : m= -\frac{1}{4}
  • Then set up your equation using the given ordered paired to find your y-intersept: -1 = -\frac{1}{4} (5) + b
  • Caluclate the product: -1 = -\frac{5}{4} + b
  • Move the variable to the left-hand side and change its sign : -b - 1 = -\frac{5}{4}
  • Calculate the sum: -b = - \frac{1}{4}
  • Change the sign : b= \frac{1}{4}
  • Use the slope and y-intersept to creat the equation: y = -\frac{1}{4}x + \frac{1}{4}
6 0
3 years ago
When rounded to the nearest tenth, which of the following values equals 9.4?
Gre4nikov [31]

Answer:

i think B would be accurate

Step-by-step explanation:

3 0
4 years ago
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