Find the endpoint/midpoint.Please hurry
2 answers:
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Answer:
We conclude that all the points of the table satisfy the equation y = x²
Hence, the option containing the equation y = x² is true.
The graph of y = x² is also attached below.
Step-by-step explanation:
Given the table
x y
-2 4
-1 1
0 0
1 1
2 4
Let us substitute the x-values of the table in the equation
y = x²
plun in x = -2
y = (-2)² = 4
so the point (2, 4) lies on the graph of y = x²
y = x²
plun in x = -1
y = (-1)² = 1
so the point (-1, 1) lies on the graph of y = x²
y = x²
plun in x = 0
y = (0)² = 0
so the point (0, 0) lies on the graph of y = x²
y = x²
plun in x = 1
y = (1)² = 1
so the point (1, 1) lies on the graph of y = x²
y = x²
plun in x = 2
y = (2)² = 4
so the point (2, 4) lies on the graph of y = x²
Therefore, we conclude from the above calculations that all the points of the table satisfy the equation y = x²
Hence, the option containing the equation y = x² is true.
The graph of y = x² is also attached below.
