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barxatty [35]
3 years ago
8

HERE PLEASE HELP MEEEEE!!!!!!!!!!!!!11

Mathematics
2 answers:
Ierofanga [76]3 years ago
8 0

The answer is the first choice.

choli [55]3 years ago
8 0

Answer: the correct answer is a

Step-by-step explanation:

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Find the volume of a right circular cone that has a height of 17.6 m and a base with a
Firlakuza [10]

Answer:

1179m^3

Step-by-step explanation:

Given radius=8m

Height=17.6m

Volume of the cone=1/3πr^2h

1/3 πr^2h

=1/3×3.14×8×8×17.6

=1178.96

Nearest tenth is 1179

So volume is 1179m^3

5 0
3 years ago
PLEASE HELP what is the vertex of the parabola? y + 1 = -1/4(x - 2)^2
inessss [21]

Answer:

(2,-1)

Step-by-step explanation:

Rewrite in vertex form

y = -1/4(x-2)^2-1

5 0
3 years ago
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solniwko [45]

Answer:

The answer is that Regina is absolutely right

Step-by-step explanation:

Hello!

The answer is that Regina is absolutely right, this is because the fundamental theorem of algebra states that every polynomial equation has the same number of solutions as its highest exponent, for this case it is 2. Therefore, there are two values of X that cause the equation to result in zero

8 0
3 years ago
Which of the following makes sense as an answer to 8.9 *7.15
V125BC [204]

Answer:

so whats the answer

Step-by-step explanation:

5 0
2 years ago
The time it takes you to go a certain distance varies inversely with the speed of travel. Suppose it takes you 4 hours to get to
fgiga [73]
\bf \qquad \qquad \textit{inverse proportional variation}
\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad  y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------

\bf \textit{time it takes varies inversely with the speed rate}\qquad \stackrel{time}{t}=\cfrac{k}{\stackrel{rate}{r}}
\\\\\\
\textit{we also know that }
\begin{cases}
t=\stackrel{hrs}{4}\\
r=\stackrel{mph}{50}
\end{cases}\implies 4=\cfrac{k}{50}\implies 200=k
\\\\\\
\boxed{t=\cfrac{200}{r}}
\\\\\\
\textit{if your rate r = 40, what is your distance \underline{t}?}\qquad t=\cfrac{200}{40}
3 0
3 years ago
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