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muminat
2 years ago
13

Can someone help me plz

Mathematics
1 answer:
wolverine [178]2 years ago
5 0

Answer:

875 ft²

Step-by-step explanation:

Given 2 similar rectangles with ratio of sides = a : b, then

ratio of areas = a² : b²

Here the ratio of sides = 5 : 25 = 1 : 5, thus

ratio of areas = 1² : 5² = 1 : 25

Thus the area of EFGH is 25 times the area of ABCD

area of EFGH = 35 × 25 = 875 ft²

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If there were 5 million births in a particular country and 3 comma 375 sets of naturally occurring​ triplets, what is the experi
IgorLugansk [536]

Answer:

Probablity =P=6.75*10^-^4

Step-by-step explanation:

The experimental probability can be defined as the ratio of the number of times any particular event has occurred to the total number of times that event has taken place.

Experimental probability = P = No. of event occurrences / total number of occurrences.

In our question statement,

No of naturally occurring triplets are = 3375

Total number of births = 5 million = 5,000,000

Putting values in equation.

P=3375/5000000

P = 0.000675\\P=6.75*10^-^4

4 0
3 years ago
3 + x + 1 = 2<br><br> Thank you :)
Lina20 [59]

Answer:

x = -2

Step-by-step explanation:

Please mark Brainliest when able, for showing work.

8 0
3 years ago
A person on a runway sees a plane approaching. The angle of elevation from the runway to the plane is 11.1° . The altitude of th
Gnoma [55]

Answer:

The horizontal distance from the plane to the person on the runway is 20408.16 ft.

Step-by-step explanation:

Consider the figure below,

Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner.  The angle of elevation from the runway to the plane is 11.1°

BC is the horizontal distance from the plane to the person on the runway.

We have to find distance BC,

Using trigonometric ratio,

\tan\theta=\frac{Perpendicular}{base}

Here, \theta=11.1^{\circ} ,Perpendicular AB = 4000

\tan\theta=\frac{AB}{BC}

\tan 11.1^{\circ} =\frac{4000}{BC}

Solving for BC, we get,

BC=\frac{4000}{\tan 11.1^{\circ} }

BC=\frac{4000}{0.196} (approx)

BC=20408.16(approx)  

Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft

8 0
2 years ago
Simplify – 5(7 + x) + 2x.
IgorLugansk [536]

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
Read 2 more answers
Why is the value of q?
Rudiy27

Given:

QSR is a right triangle.

QT = 10

TR = 4

To find:

The value of q.

Solution:

Hypotenuse of QSR = QT + TR

                                 = 10 + 4

                                 = 14

Geometric mean of similar right triangle formula:

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{14}{q} =\frac{q}{4}

Do cross multiplication.

$\Rightarrow14\times 4 =q\times q

$\Rightarrow 56 =q^2

Switch the sides.

$\Rightarrow q^2 =56

Taking square root on both sides.

\Rightarrow q =2 \sqrt{14}

The value of q is 2 \sqrt{14}.

8 0
3 years ago
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