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3 years ago

What is 1/4 + 2/4 Good luck

Mathematics

1 answer:

Tcecarenko [31]3 years ago

4 0

Answer:

$\frac{1}{4}+\frac{2}{4}=\frac{3}{4}$

Step-by-step explanation:

To evaluate:

$\frac{1}{4}+\frac{2}{4}$

Since the fractions have a common denominator, so we can simply add the numerators keeping the denominator as it is.

⇒ $\frac{1+2}{4}$

⇒ $\frac{3}{4}$

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3 years ago

Write the equation of the line that passes through (1, 3) and has a slope of 2 in point-slope form. A) y – 1 = 2(x – 3) B) y – 3

fomenos

So point slope form is y=mx+b where m=slope and b=y intercept so

in (x,y) form
one solution is x=1 and y=3, also slope is 2 so
m=2
subsitute
3=2(1)+b
3=2+b
subtract 2
1=b
equation is
y=2x+1

tricky answers so simplify them
A: y-1=2(x-3)
distribute
y-1=2x-6
add 1
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not the answer

B: y-3=2(x-1)
distribute
y-3=2x-2
add 3
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3 years ago

What are the domain restrictions of the expression g2−7g+10g3−6g2+8g ? Select each correct answer.

Sauron [17]

Answer with Step-by-step explanation:

We are given that an expression

$f(g)=\frac{g^2-7g+10}{g^3-6g^2+8g}$

We have to find domain restriction of the given function.

$f(g)=\frac{(g-5)(g-2)}{g(g-4)(g-2)}$

Domain restriction means : It is that value of x when substitute in function then function will not defined.

It means it is that values which makes denominator zero.

From given function we can see that

When substitute g=0 then it makes denominator zero.

Hence, the function is not defined at g=0

Substitute g=4

Then, it makes denominator zero.

Hence, function is not defined at g=4

Substitute g=2

Then,it makes denominator zero.

Hence, function is not defined at g=2

Therefore, the function is defined for all values of g except g=0, g=2 and g=4

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3 years ago