Answer:
Here is the number of juice boxes
Step-by-step explanation:
No matter what source there is, you will always appear to end up finding out that there are precisely 69 juice boxes
Using the binomial distribution, the probabilities are given as follows:
- 0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
- 0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
- Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
<h3>What is the binomial distribution formula?</h3>
The formula is:
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
The values of the parameters for this problem are:
n = 10, p = 0.4.
The probability that more than 4 weigh more than 20 pounds is:
In which:
Then:
Hence:
0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
The probability that fewer than 3 weigh more than 20 pounds is:
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673
0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
For more than 7, the probability is:
Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.
More can be learned about the binomial distribution at brainly.com/question/24863377
#SPJ1
Answer:
-5
Step-by-step explanation:
4x - 1 = 6x + 9
4x = 6x + 10
-2x = 10
x = -5
Section A has 27000 seats
Section B has 14200 seats
and Section C has 12800 seats.
u = 1+3e<span>-x</span>
so that (Don't forget to use the chain rule on e<span>-x</span>.)
du = 3e<span>-x</span>(-1) dx = -3e<span>-x</span> dx ,
or
(-1/3)du = e<span>-x</span> dx .
However, how can we replace the term e<span>-3x</span> in the original problem ? Note that
.
From the u-substitution
u = 1+3e<span>-x</span> ,
we can "back substitute" with
e<span>-x</span> = (1/3)(u-1) .
Substitute into the original problem, replacing all forms of x, getting
(Recall that (AB)C = AC BC .)