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Tamiku [17]
3 years ago
14

When is the best time to speak only terse words?

Mathematics
1 answer:
Greeley [361]3 years ago
7 0
When you have all your information 
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NO websites or fake links, inappropriate comments, wired, or not helping comments our your reported and show me your steps to ea
Musya8 [376]
I couldn’t put the answer here here’s a link! Good luck!

Iwaskidding.lol

1. Is 2(1/3)
2. Is 4(1/5)
3. Is 3(1/9)
4. Is 4(1/2)
5. Is 3(1/12)

This is just an educated guess so please think about my answers carefully. Have a good day.
8 0
3 years ago
What’s the first 1st term in the sequence given by :T(n)=n^2-4<br> Pls help
Zepler [3.9K]

First term = T(1) is obtained by plugging  n = 1 into the formula,

thus First term = 1^2 - 4 = 1 - 4

= 3    (answer)

8 0
3 years ago
2.A production process manufactures items with weights that are normally distributed with mean 10 pounds and standard deviation
Vesna [10]

Answer:

Step-by-step explanation:

Given that:

population mean = 10

standard deviation = 0.1

sample mean = 9.8 < x > 10.2

The z score can be computed as:

z = \dfrac{\bar x - \mu}{\sigma}

if x > 10.2

z = \dfrac{10.2- 10}{0.1}

z = \dfrac{0.2}{0.1}

z = 2

If x < 9.8

z = \dfrac{9.8- 10}{0.1}

z = \dfrac{-0.2}{0.1}

z = -2

The p-value = P (z ≤ 2) + P (z ≥ 2)

The p-value = P (z ≤ 2) + ( 1 -  P (z ≥ 2)

p-value = 0.022750 +(1 -   0.97725)

p-value = 0.022750 +  0.022750

p-value = 0.0455

Therefore; the probability of defectives  = 4.55%

the probability of acceptable = 1 - the probability of defectives

the probability of acceptable = 1 - 0.0455

the probability of acceptable = 0.9545

the probability of acceptable = 95.45%

4.55% are defective or 95.45% is acceptable.

sampling distribution of proportions:

sample size n=1000

p = 0.0455

The z - score for this distribution at most 5% of the items is;

z = \dfrac{0.05 - 0.0455}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{0.0045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = \dfrac{0.0045}{\sqrt{4.342975 \times 10^{-5}}}

z = 0.6828

The p-value = P(z ≤ 0.6828)

From the z tables

p-value = 0.7526

Thus, the probability that at most 5% of the items in a given batch will be defective = 0.7526

The z - score for this distribution for at least 85% of the items is;

z = \dfrac{0.85 - 0.9545}{\sqrt{\dfrac{0.0455\times 0.9545}{1000}}}

z = \dfrac{-0.1045}{\sqrt{\dfrac{0.04342975}{1000}}}

z = −15.86

p-value = P(z ≥  -15.86)

p-value = 1 - P(z <  -15.86)

p-value = 1 - 0

p-value = 1

Thus, the probability that at least 85% of these items in a given batch will be acceptable = 1

6 0
3 years ago
a box is 24cm by 15cm by 10cm. this box will packed with smaller boxes of paper clips which are 6cm by 3cm by 5cm . what is the
vichka [17]

Answer: 40

Align in this pattern:

Bigger box : 24 : 15 : 10

smaller box: 6 : 3 : 5

counts: 4: 5 : 2

( multiply 4*5*2 = 40)

7 0
3 years ago
3 5/6 x 8 as a fraction
kirza4 [7]

Answer: 92/3 OR 30 2/3 ??

Step-by-step explanation:

3 0
3 years ago
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