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MA_775_DIABLO [31]
3 years ago
15

Which statement is equivalent to the inequality | x-3 | > 5

Mathematics
1 answer:
DENIUS [597]3 years ago
8 0
  1. <em><u>Abcdefghijklmnopqrstuvwxyz</u></em>

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In ΔCDE, \overline{CE}
abruzzese [7]

Answer:

m\angle CDE=14^o

Step-by-step explanation:

we know that

An exterior angle of a triangle is equal to the sum of the opposite interior angles.

see the attached figure to better understand the problem

so

∠DEF=∠ECD+∠CDE

substitute the given values

(4x+5)^o=(x+9)^o+(x+8)^o

solve for x

Combine like terms

(4x+5)^o=(2x+17)^o

Group terms

4x-2x=17-5

2x=12

x=6

Find the measure of angle CDE

m\angle CDE=(x+8)^o

substitute the value of x

m\angle CDE=(6+8)=14^o

8 0
3 years ago
At what value of x does the graph of the following function F(x) have a
Free_Kalibri [48]

Answer:

B

Step-by-step explanation:

Given

f(x) = \frac{1}{x+2}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

6 0
3 years ago
Explain how to add fractions with unlike denominators. Please be as specific as possible.
Gelneren [198K]

Answer:

Look below

Step-by-step explanation:

So I will use an example to try and show you how to do this.

If we have 1/2 + 1/3, we know that we don't have like denominators. We can change this by finding one. All we need to do is multiply our denominators. So in our example, that would be 2*3=6. Our new denominator would be 6. So now we would have 1/6 + 1/6 which isn't the same as our old equation. That is because we haven't multiplied our top numbers yet. To do this, we need to multiply the top number by the opposite denominator like so, 3/6+2/6.

So our first fraction was

1/2+1/3

We then multiplied the whole fraction by the opposite denominator

3/6+2/6

Thanks! Hope you choose me for brainliest!!! Have a nice day!

5 0
3 years ago
All the info is in the pictures
Hunter-Best [27]
Bearing in mind that an absolute value expression is in effect a piece-wise function with two cases, thus

\bf |-n|=&#10;\begin{cases}&#10;+(-n)\\&#10;-(-n)&#10;\end{cases}\implies &#10;\begin{cases}&#10;-n\\&#10;n&#10;\end{cases}&#10;\\\\\\&#10;n|-n|=2n\implies &#10;\begin{cases}&#10;n-n=2n\implies 0=2n\implies &0=n\\&#10;n+n=2n\implies 2n=2n\impliedby &inconsistent&#10;\end{cases}
6 0
3 years ago
I need the answer please help me straight away!!!
Neko [114]

Answer:

15

Step-by-step explanation:

8 0
3 years ago
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