A quadrilateral is said to be a parallelogram
1.Opposite sides are equal and parallel.
2. Diagonal bisect each other.
3. Opposite angles are equal.
It is given that , a Parrallelogram is graphed on a coordinate plane so the two points are in the first quadrant and two points are in the third quadrant.
Suppose ABCD is a Parallelogram.Then AB=CD and AD=BC.
Given, Vertices A,B lies in first Quadrant and Vertices C and D lies in Third Quadrant.Then Vertices of Parallelogram ABCD are
A=( x, y) and B=( y, x)
Then, C= (- x,- y) and D= (- y,- x), Arranged in Alphabetical order, that is A,B and C and D.
The range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
<h3>Range</h3>
Given
592<x1317
74.35+.25
Hence:
Lowest range
74.35+.25(600-592)
74.35+.25(8)
74.35+2
=76.35
Highest range
74.35+.25(700-592)
74.35+.25(108)
74.35+27
=101.35
Range
76.35<x<101.35
Therefore the range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
Learn more about range here: brainly.com/question/2264373
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Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
It is the answer
Hope to help this with u
Just be happy all the times
Answer:
tan 33° = 25/x
Step-by-step explanation:
hope it helps
