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podryga [215]
3 years ago
7

How do I do this? I know the shapes and everything but how do I do b, d, and e?

Computers and Technology
1 answer:
aleksandr82 [10.1K]3 years ago
4 0
Look in google for math flowcharts...it will appear easily.
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Create a simple program of your own using a Loop that counts and displays numbers 1-10.
avanturin [10]

Answer:

I think

Explanation:

you....

8 0
3 years ago
Which of the following are all involved in the evaluation of the presentation of a speech?
ikadub [295]

Answer:

C.

Explanation:

The elements involved in the evaluation of the presentation of a speech includes visual aids, vocal technique, and body language.

Adding vivid pictures in the presentation makes it graphic and proficient. The visual aids in presentation also provides the succinct and clear meaning of the message to the reader.

The vocal technique is another element that adds value in presentation. A speaker's confidence is reflected through his/her tone. It is the speaker's voice that becomes an influential tool that draws the audience's attention.

Body language, like vocal technique, helps in effective delivering of the speech. Body language is a non-verbal form of communicatin that communicates a lot to the audience than one can imagine.

Therefore, option C is correct.

6 0
3 years ago
&gt;&gt;&gt; phrase = "abcdefgh" <br><br> &gt;&gt;&gt; phrase[3:6]
Scrat [10]

Answer:

Following are the correct code to this question:

phrase = "abcdefgh"#defining a variable phrase that holds a string value

print(phrase[3:6])#use print method for slicing and print its value

Output:

def

Explanation:

In the above code, a variable "phrase" is defined that holds a string value, and use a print method, inside the method, the variable is used as a list and use slicing.

It is a characteristic that enables you to access the series parts like strings, tuples, and lists. It also uses for modifying or removing objects in series, in the above slicing it starts from 3 and ends when it equal to the 6th letter, that's why it will print "def".

6 0
3 years ago
The application reliability team at your company this added a debug feature to their backend service to send all server events t
Paraphin [41]

Answer:

The correct answer to the following question will be Option A.

Explanation:

The given question is incomplete and the complete question will be:

The event records are at least 50 KB and at most 15 MB and are expected to peak at 3,000 events per second. You want to minimize data loss. Which process should you implement?

Append metadata to file the body.

Compress individual files.

Name files with a random prefix pattern.

Save files to one bucket

(B)

Batch every 10,000 events with a single manifest file for metadata.

Compress event files and manifest files into a single archive file.

Name files using serverName-EventSequence.

Create a new bucket if a bucket is older than 1 day and save the single archive file to the new bucket. Otherwise, save the single archive file to the existing bucket.

(C)

Compress individual files.

Name files with serverName-EventSequence.

Save files to one bucket

Set custom metadata headers for each object after saving.

(D)

Append metadata to file the body.

Compress individual files.

Name files with serverName-Timestamp.

Create a new bucket if the bucket is older than 1 hour and save individual files to the new bucket. Otherwise, save files to the existing bucket.

  • Therefore, in option A, a name file can be used with a prefix pattern randomly. So, it will be the right answer
  • The other three options such as C, B and D are incorrect because they are using name files with "serverName-EventSequence" or "serverName-Timestamp" which causes the distribution in the backend irregularly.

7 0
4 years ago
Consider a file system that uses inodes to represent files. Disk blocks are 8KB in size, and a pointer to a disk block requires
insens350 [35]

Answer:

64 terabytes

Explanation:

Given data:

Size of the disk block = 8 KB

Size required by the pointer to a disk block = 4 bytes

Now,

Size required by 12 direct disk blocks = 12 × 8

Size required by single disk block = 2048 × 8 KB

Size required by double disk block = 2048 × 2048 × 8 KB

size  required by triple disk block = 2048 × 2048 × 2048 × 8 KB

Now,

the maximum size of the file that can be stored in the this file system = 12 × 8  + 2048 × 8 KB  +  2048 × 2048 × 8 KB + 2048 × 2048 × 2048 × 8 KB  = 64 terabytes

5 0
4 years ago
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